answer:
an opaque object is one that doesn't let light pass through it. instead, it reflects or absorbs the light that strikes it.
explanation:
in this case, we see the material because of the transmitted light. therefore, the wavelength of the transmitted light determines the color that the object appears.
good luck :)
i hope this helps
have a nice day !!
Answer:
A) The elastic potential energy stored in the spring when it is compressed 0.10 m is 0.25 J.
B) The maximum speed of the plastic sphere will be 2.2 m/s
Explanation:
Hi there!
I´ve found the complete problem on the web:
<em>A toy launcher that is used to launch small plastic spheres horizontally contains a spring with a spring constant of 50. newtons per meter. The spring is compressed a distance of 0.10 meter when the launcher is ready to launch a plastic sphere.</em>
<em>A) Determine the elastic potential energy stored in the spring when the launcher is ready to launch a plastic sphere.</em>
<em>B) The spring is released and a 0.10-kilogram plastic sphere is fired from the launcher. Calculate the maximum speed with which the plastic sphere will be launched. [Neglect friction.] [Show all work, including the equation and substitution with units.]</em>
<em />
A) The elastic potential energy (EPE) is calculated as follows:
EPE = 1/2 · k · x²
Where:
k = spring constant.
x = compressing distance
EPE = 1/2 · 50 N/m · (0.10 m)²
EPE = 0.25 J
The elastic potential energy stored in the spring when it is compressed 0.10 m is 0.25 J.
B) Since there is no friction, all the stored potential energy will be converted into kinetic energy when the spring is released. The equation of kinetic energy (KE) is the following:
KE = 1/2 · m · v²
Where:
m = mass of the sphere.
v = velocity
The kinetic energy of the sphere will be equal to the initial elastic potential energy:
KE = EPE = 1/2 · m · v²
0.25 J = 1/2 · 0.10 kg · v²
2 · 0.25 J / 0.10 kg = v²
v = 2.2 m/s
The maximum speed of the plastic sphere will be 2.2 m/s
the answer is cancer is often named according to what body type it affects
Assuming that you have a triangular prism, the ray of light will undergo refraction twice. The first time is the transition from air to flint glass on the entry face, and the second time is the transition from the flint glass to air from the exit face. With the available data, there are two possible solution since saying "20Âş from the normal" isn't enough information. Depending upon which side of the normal that 20 degrees is, the interior triangle will have the angles of 35, 90-r, and 55+r, or 35, 90+r, 55-r degrees where r is the angle from the normal after the 1st refraction. I will provide both possible solutions and you'll need to actually select the correct one based upon the actual geometry which I don't know because you didn't provide the figure or diagram that you were provided with.
The equation for refraction is:
(sin a1)/(sin a2) = n1/n2
where
a1,a2 = angles from the normal to the surface.
n1,n2 = index of refraction for the transmission mediums.
For this problem, we've been given an a1 of 20Âş and an n1 of 1.60. For n2, we will use air which at STP has an index of refraction of 1.00029. So
(sin a1)/(sin a2) = n1/n2
(sin 20)/(sin a2) = 1.00029/1.60
0.342020143/(sin a2) = 0.62518125
0.342020143 = 0.62518125(sin a2)
0.547073578 = sin a2
asin(0.547073578) = a2
33.16647891 = a2
So the angle from the normal INSIDE the prism is 33.2Âş. The resulting angle from the surface of the entry face will be either 90-33.2 or 90+33.2 depending upon the geometry. So the 2 possible triangles will be either 35Âş, 56.8Âş, 88.2Âş or 35Âş, 123.2Âş, 21.8Âş. with a resulting angle from the normal of either 1.8Âş or 68.2Âş. I can't tell you which one is correct since you didn't tell me which side of the normal the incoming ray came from. So let's calculate both possible exits.
1.8Âş
(sin a1)/(sin a2) = n1/n2
(sin 1.8)/(sin a2) = 1.6/1.00029
0.031410759/(sin a2) = 1.599536135
0.031410759= 1.599536135(sin a2)
0.019637418= sin(a2)
asin(0.019637418) = a2
1.125213477 = a2
68.2Âş
(sin a1)/(sin a2) = n1/n2
(sin 68.2)/(sin a2) = 1.6/1.00029
0.928485827/(sin a2) = 1.599536135
0.928485827 = 1.599536135(sin a2)
0.58047193 = sin a2
asin(0.58047193) = a2
35.48374252 = a2
So if the interior triangle is acute, the answer is 1.13Âş and if the interior triangle is obtuse, the answer is 35.48Âş
A I think it was sorry if not
