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3 years ago

Which of the following can be used to neutralize an ammonia (NH3) solution?

2 answers:

8 0

It would have been much better if you had attached some options to choose. But I think I've got what you mean. I bet that solution is HCl.

tensa zangetsu [6.8K]3 years ago

5 0

It really depends on your options.
Since NH3 solution is a weak base, the option that neutralizes a base is an acid. So find an acid among your options, and here are some examples: HNO3, HCl, etc.

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HEEELP! :)

Nadusha1986 [10]

A substance can dissolve in another when they have thee same type of intermolecular interaction.

<h3>What is solubility?</h3>

The term solubility of a solute refers to the extent to which a solute dissolve in a solvent. We must know that a substance can dissolve in another when they have thee same type of intermolecular interaction.

Thus;

a) Octane (C8H18) mixes well with CCl4 because they are both non polar substances.

b) Methanol (CH3OH) is mixed with water in all ratios because the both are polar substances.

c) NaBr dissolves very poorly in acetone (CH3 ― CO ― CH3) because acetone is only slightly polar.

Learn more about solubility:brainly.com/question/8591226

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8 0

2 years ago

4. Which atomic particles are found inside the nucleus of an atom?

grin007 [14]

Answer:

the atomic particles in the necluse are called ions which are positive and negive charged atoms

Explanation:

6 0

4 years ago

What 3 gases does the flame test check for and what should you expect to see/hear?

Kazeer [188]

What of the gasses is N and the flame changes it's color from Orange to blue

7 0

4 years ago

What attractive forces must be overcome when CsI is dissolvedin liquid HF?

bagirrra123 [75]

Answer:

The attractive forces must be overcome are :

Ion- ion interaction

Dipole - Dipole

Hydrogen Bonding

Explanation:

For the compound to dissolve the attractive forces existing between atoms of the compound must be reduced

CsI is ionic compound and its molecules are held together by ionic(electrostatic) force . These force must be weakened for its dissolution

Forces in HF :

1 .Hydrogen Bonding : In HF strong intermolecular Hydrogen Bonding exist between the electronegative F and Hydrogen

2. Dipole - dipole : HF is polar . So it is a permanent dipole and has dipole diople interaction

4 0

3 years ago

Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose

Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution = 101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0

3 years ago