1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MakcuM [25]
3 years ago
9

Which of the following can be used to neutralize an ammonia (NH3) solution?

Chemistry
2 answers:
alisha [4.7K]3 years ago
8 0
It would have been much better if you had attached some options to choose. But I think I've got what you mean. I bet that solution is <span>HCl.</span>
tensa zangetsu [6.8K]3 years ago
5 0
It really depends on your options. 
Since NH3 solution is a weak base, the option that neutralizes a base is an acid. So find an acid among your options, and here are some examples: HNO3, HCl, etc.
You might be interested in
An unknown gas is found to diffuse through a porous membrane 4.11 times more slowly than h2 what is the molecular weight of the
kirill [66]
To answer this question, you need to know <span>Graham's Law of Effusion/Diffusion formula. In this formula, the rate of diffusion/effusion would be influenced by the mass. As the molecule has bigger mass, the rate should be slower because it will be harder to pass the membrane. The calculation should be:</span>
<span>Rate 1 / Rate 2 = √[M2/M1] 
</span>4.11/1= √[M2/2] 
M2=33.78 g/mol

5 0
3 years ago
Read 2 more answers
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
An ionic compound has a very negative heat of solution in water. Would you expect it to be soluble or insoluble in water?.
ddd [48]

Answer:

It will be Insolube in water

8 0
3 years ago
The specific heat of copper metal is 0. 385 J/(g °C). How much energy must be added to a 35. 0-gram sample of copper to change t
Rus_ich [418]

The amount of heat required for changing the temperature of copper has been 606 J. Thus, option B is correct.

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The heat required to raise the temperature has been expressed as:

\rm Heat=mass\;\times\;specific\;heat\;\times\;Change\;in\;temperature

<h3>Computation for the heat energy required</h3>

The given specific heat of copper has been \rm 0.385\;J/g^\circ C

The mass of copper has been, \rm 35\;g

The initial temperature of copper has been, \rm 20^\circ C

The final temperature of copper has been, \rm 65^\circ C

The change in temperature has been, \Delta T

\Delta T=\text{Final\;temperature-Initial\;temperature}\\\Delta T =65^\circ \text C-20^\circ \text C\\\Delta T=45^\circ \text C

Substituting the values for the heat required as:

\rm Heat=35\;g\;\times\;0.385\;J/g^\circ C\;\times\;45^\circ C\\Heat=606\;J

The amount of heat required for changing the temperature of copper has been 606 J. Thus, option B is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

7 0
2 years ago
Where does the largest percent of water exist on Earth?
Ivanshal [37]

Answer:

97% of earth's water is in the ocean. The rest could be found underground, in glaciers and ice, and in rivers and lakes

3 0
3 years ago
Other questions:
  • Describe the different types of solutions that can be formed by the combination of solids, liquids, and gases
    5·1 answer
  • Explain why it is more difficult to measure the temperature of a solid than of a liquid
    14·2 answers
  • Consider the reaction C2H4(g) + H2O(g) --&gt; CH3CH2OH(g)
    6·1 answer
  • MgO + H2O = Mg(OH)2 is an example of a _____ chemical reaction.
    6·1 answer
  • Find the area of a circle inscribed in an equilateral triangle of side 18 cm. ( Take pi= 3.14).​ answer should be 54.78 cm²
    8·1 answer
  • The Lewis dot diagram for LiBr
    9·1 answer
  • PLEASE HELPPPP!!! IM BEING TIMED
    5·2 answers
  • Which solution whose POH is 12
    8·1 answer
  • What is the mass percentage of Li2CO3
    14·1 answer
  • Recall that you're hypothesis is that these values are the fractions of atoms that are still radioactive after n half life cycle
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!