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podryga [215]
3 years ago
14

What is the chemical equation for the alpha decay of erbium-144

Chemistry
1 answer:
iren [92.7K]3 years ago
8 0

Answer:

Er-144 -------> Dy-140 + He-4

Explanation:

Alpha decay is the release of a hydrogen nucleus.  So the original atom will decrease the mass by 4 and the atomic number by 2.

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Which option best characterizes the following scenario?
Lisa [10]

Answer:

Externalities are costs (negative externalities) or benefits (positive externalities), which are not reflected in free market prices. ... Market failure is a situation in which the free market leads to a misallocation of society's scarce ... and the killing of fish is not a cost that it would directly have to bear

7 0
3 years ago
Is zn2+ a transition metal?​
4vir4ik [10]

Answer:

Yes.

Explanation:

Zn2+ is the zinc ion in aqueous solution.

Zinc is a transition metal.

These metals are in the middle of the periodic table and have similar properties.

7 0
3 years ago
Active
klio [65]

Option B

Primary productivity is not limited by time

<u>Explanation:</u>

To ecosystems, the productivity of the primary producers is essential because certain bodies generate energy for different existence bodies. Besides the era, primary production ends in the extension of dissimilar plant biomass to the practice. Consumers acquire their strength from primary producers, unless directly (herbivores, any detritivores), or diffusely.

It depends superimposed on the availability of the sunlight, availability of the nutrients such as nitrogen, iron, phosphorus from the soil and water. The primary productivity of the plant's distinct autotrophs is not restricted by time.

5 0
3 years ago
Consider separate solutions of NaOH and KClmade by dissolving 100.0 g of each solute in 250.0 mL of solution. Calculate the conc
gladu [14]

Answer:

Explanation:

MW of NaOH = 40 g/mol

MW of KCl = 74.55 g/mp;

250 mL = .25 L

100g NaOH / 40 g = 25 mol

100g KCl/ 74.55g = 1.34 mol

Molarity of NaOH: 25/.25 = 100M

Molarity of KCl: 1.34/.25 = 5.36 M

8 0
2 years ago
Balance the following reaction:
kvv77 [185]
  • C_5H_8+13/2O_2—»5CO_2+4H_2O

Balanced one

  • 2C_5H_8+13O_2—»10CO_2+8H_2O

Moles of Pentyne

  • Given mass/Molarmass
  • 34/68
  • 0.5mol

Moles of H_2O

  • 8/2(0.5)
  • 4(0.5)
  • 2mol

1mol releases 241.8KJ

2mol releases 241.8(2)=483.6KJ

8 0
1 year ago
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