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san4es73 [151]
3 years ago
14

Consider two adjacent states, S1 and S2, that wish to control particulate emissions from power plants and cement plants; New Jer

sey and Pennsylvania, for example. Each state wants to remove all particulates larger than 100 nanometres from the airspace below 1000 feet. Suppose this requires 50 kilotons of abatement in each state. The aggregate cost of abatement when the marginal abatement costs of all industries within the state are equalized is 3A21 for state S1 and it is A2 for state S2, where Ai is measured in kilotons.(a) If the states do not cooperate, what is the cost of abatement in state S1?(b) Would a permit market with 50 kilotons of emissions permits distributed to the firms by means of an ascending clock auction equate the marginal abatement costs of all power and cement firms within state S1? You may assume that no firms are bankrupted.(c) If the states do not cooperate, what is the cost of abatement in state S2?(d) If the states do cooperate by means of a 100 kiloton cap and a permit market that covers both states with permits allocated by an ascending clock auction, what is the total cost of abatement? You may assume that no firms are bankrupted. You may also assume that a joint auction will not change the aggregate cost functions 3A21 for state S1 and A2 for state S2.(e) Why does the sum of the costs of abatement from question 1a and 1c not equal the cost of abatement in question 1d?

Physics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

a. 7500

b. Yes

c. 2500

d. 7500

Explanation:

Please see attachment

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bija089 [108]

Answer:

1411.8 N/m

Explanation:

From Hooke's law;

F= Ke

Where

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K= force constant

e = extension

But e= 8.50 × 10^-2m

F= weight = 12.0 kg × 10 = 120 N

K = F/e = 120/8.50 × 10^-2

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Light shines through a single slit whose width is 5.7 x 10-4 m. A diffraction pattern is formed on a flat screen located 4.0 m a
lilavasa [31]

Answer:

\lambda = 570\ nm

Explanation:

Given,

Width of slit, W = 5.7 x 10⁻⁴ m

Distance between central bright fringe, L = 4 m

distance between central bright fringe and first dark fringe, y = 4 mm

Diffraction angle

tan \theta = \dfrac{y}{L}

tan \theta = \dfrac{4}{4\times 10^3}

\theta = 0.0572

Now.

W sin \theta = m \lambda

m = 1

5.7 \times 10^{-4} \times sin (0.0572) = 1 \times \lambda

\lambda = 569.99 \times 10^{-9}\ m

\lambda = 570\ nm

4 0
3 years ago
Which statement is true? The speed of sound in air is inversely proportional to the temperature of the air. The speed of sound i
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6 0
2 years ago
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4 0
3 years ago
Suppose we have a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it trie
sammy [17]

Answer:

2.64 m/s

Explanation:

Given that a 600 kilogram great "yellow" shark swimming to the right at a speed of 3 meters traveled each second as it tries to get lunch. An unsuspecting 100 kilogram blue fin tuna is minding its own business swimming to the left at a speed of 0.5 meters traveled each second. GULP! After the great "yellow" shark "collides" with the blue fin tuna

Momentum = MV

Momentum of the yellow shark before collision = 600 × 3 = 1800 kgm/s

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Total momentum before collision = 1800 + 50 = 1850 kgm/s

Let's assume that they move together after collision. Then,

1850 = ( 600 + 100 ) V

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V = 1850 / 700

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