Consider two adjacent states, S1 and S2, that wish to control particulate emissions from power plants and cement plants; New Jer
sey and Pennsylvania, for example. Each state wants to remove all particulates larger than 100 nanometres from the airspace below 1000 feet. Suppose this requires 50 kilotons of abatement in each state. The aggregate cost of abatement when the marginal abatement costs of all industries within the state are equalized is 3A21 for state S1 and it is A2 for state S2, where Ai is measured in kilotons.(a) If the states do not cooperate, what is the cost of abatement in state S1?(b) Would a permit market with 50 kilotons of emissions permits distributed to the firms by means of an ascending clock auction equate the marginal abatement costs of all power and cement firms within state S1? You may assume that no firms are bankrupted.(c) If the states do not cooperate, what is the cost of abatement in state S2?(d) If the states do cooperate by means of a 100 kiloton cap and a permit market that covers both states with permits allocated by an ascending clock auction, what is the total cost of abatement? You may assume that no firms are bankrupted. You may also assume that a joint auction will not change the aggregate cost functions 3A21 for state S1 and A2 for state S2.(e) Why does the sum of the costs of abatement from question 1a and 1c not equal the cost of abatement in question 1d?
1 answer:
You might be interested in
Answer: 114
Explanation:
The mass number of an element gives the sum of the protons and the neutrons inside the nucleus of one atom of that element, while the atomic number of an element gives the number of protons inside one atom of that element.
We can infer the number of neutrons inside one atom of Osmium from its mass number and atomic number.
The atomic number of osmium is 76, so each atom of osmium has 76 protons
The (average) mass number of osmium is 190, so each atom of osmium has (on average) 190 protons+neutrons
So, in order to find the average number of neutrons, we can subtract the atomic number from the mass number: