If a wave has a frequency of 5 Hz, what is its period?
1 answer:
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Answer:
Mass of the pull is 77 kg
Explanation:
Here we have for
Since the rope moves along with pulley, we have
For the first block we have
T₁ - m₁g = -m₁a = -m₁g/4
T₁ = 3/4(m₁g) = 323.4 N
Similarly, as the acceleration of the second block is the same as the first block but in opposite direction, we have
T₂ - m₂g = m₂a = m₂g/4
T₂ = 5/4(m₂g) = 134.75 N
T₂r - T₁r = I·∝ = 0.5·M·r²(-α/r)
∴
Mass of the pull = 77 kg.
Answer:
a)
b)
Explanation:
From the question we are told that:
Distance between wires
Wire 1 current
Wire 2 current
a)
Generally the equation for Force on due to
is mathematically given by
Where
B_2=Magnetic field current by
Therefore
b)
Generally the equation for Force on due to
is mathematically given by
Where
B_1=Magnetic field current by
Therefore