A pipe produces successive harmonics at 300 Hz and 350 Hz. Calculate the length of the pipe and state whether it is closed at on
1 answer:
Answer:
The pipe is open ended and the length of pipe is 3.4 m.
Explanation:
For identification of the type of pipe checking the successive frequencies in both the open pipe and closed pipe as below
Equation for nth frequency for open end pipe is given as
For (n+1)th value the frequency is
Taking a ratio of both equation and solving for n such that the value of n is a whole number
So n is a whole number this means that the pipe is open ended.
For confirmation the nth frequency for a closed ended pipe is given as
For (n+1)th value the frequency is
Taking a ratio of both equation and solving for n such that the value of n is a whole number
As n is not a whole number so this is further confirmed that the pipe is open ended.
Now from the equation of, with n=6, v=340 m/s and f=300 Hz
The value of length is 3.4m.
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Answer:
Check the explanation
Explanation:
#include <iostream>
using namespace std;
void insert(int* arr, int* size, int value, int position){
if(position<0 || position>=*size){
cout<<"position is greater than size of the array"<<endl;
return ;
}
*size = *size + 1 ;
for(int i=*size;i>position;i--){
arr[i] = arr[i-1];
}
arr[position] = value ;
}
void print(int arr[], int size){
for(int i=0;i<size;i++){
cout<< arr[i] <<" ";
}
cout<<" "<<endl;
}
void remove(int* arr, int* size, int position){
* size = * size - 1 ;
for(int i=position;i<*size;i++){
arr[i] = arr[i+1];
}
}
int count(int arr[], int size, int target){
int total = 0 ;
for(int i=0;i<size;i++){
if(arr[i] == target)
total += 1 ;
}
return total ;
}
int main()
{
int size;
cout<<"Enter the initial size of the array:";
cin>>size;
int arr[size],val;
cout<<"Enter the values to fill the array:"<<endl;
for(int i=0;i<size;i++){
cin>>val;
arr[i] = val ;
}
int choice = 5,value,position,target ;
do{
cout<<"Make a selection:"<<endl;
cout<<"1) Insert"<<endl;
cout<<"2) Remove"<<endl;
cout<<"3) Count"<<endl;
cout<<"4) Print"<<endl;
cout<<"5) Exit"<<endl;
cout<<"Choice:";
cin>>choice;
switch(choice){
case 1:
cout << "Enter the value:";
cin>>value;
cout << "Enter the position:";
cin>>position;
insert(arr,&size,value,position);
break;
case 2:
cout << "Enter the position:";
cin>>position;
remove(arr,&size,position);
break;
case 3:
cout<<"Enter the target value:";
cin>>target;
cout <<"The number of times "<<target<<" occured in your array is:" <<count(arr,size,target)<<endl;
break;
case 4:
print(arr,size);
break;
case 5:
cout <<"Thank you..."<<endl;
break;
default:
cout << "Invalid choice..."<<endl;
}
}while(choice!=5);
return 0;
}
Kindly check the attached images below for the code output.
Answer:
when 5% excess air is supplied, moles of air supplied/moles of fuel =
Explanation:
Equivalence ratio = 0.6
Equivalence ratio = Actual air to fuel ratio (AAFR)/ stoichiometric air to fuel ratio SAFR
combustion reaction of propane is
From above reaction, 1 mole of propane, from the reaction, 5 moles of oxygen required,
we know that air contains 21% O_2 and 79% N_2,
Therefore, moles of air based on stoichiometry
Theoretical air to fuel ratio
Given
Actual Air Fuel Ratio
when 5% excess air is supplied, moles of air supplied/moles of fuel =