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3 years ago

Please help me very easy will biraly and 5 star and thanks

Chemistry

2 answers:

cestrela7 [59]3 years ago

7 0

ITS 40 GRAMS I THINK

zloy xaker [14]3 years ago

5 0

Answer:

<u>The average amount will increase. (I think)</u>

Explanation:

That's all I know

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A group of students collects data to determine whether compounds were ionic or covalent. They placed each compound in a small bo

yan [13]

Answer:

the answer is B.

No, as ionic compounds are only conductive in an aqueous (water) solution

Explanation: i just know

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3 years ago

One way to determine the empirical formula of a compound involves using the percent composition of the compound.

iragen [17]

True! You can use the percentage to determine the amount of moles of each substance in the compound, and then use that information to find the empirical formula.

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3 years ago

Rank the members of each set of compounds according to the ionic character of their bonds. Most ionic bonds?a) PCl3 PBr3 PF3 Mos

SCORPION-xisa [38]

Explanation:

More is the electronegativity difference between the combining atoms more polar is the compound. Hence, more ionic it will be in nature.

(a) Electronegativity value of P = 2.19

Electronegativity value of Cl = 3.16

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a P-Cl bond = 3.16 - 2.19 = 0.97

Electronegativity difference of a P-Br bond = 2.96 - 2.19 = 0.77

Electronegativity difference of a P-F bond = 3.98 - 2.19 = 1.79

Since, a P-F bond has the highest electronegativity difference. Therefore, $PF_{3}$ is the most ionic compound and $PBr_{3}$ is the least ionic compound.

(b) Electronegativity value of B = 2.04

Electronegativity value of N = 3.04

Electronegativity value of C = 2.55

Electronegativity value of F = 3.98

Electronegativity difference of a B-F bond = 3.98 - 2.04 = 1.94

Electronegativity difference of a N-F bond = 3.04 - 3.98 = 0.94

Electronegativity difference of a C-F bond = 3.98 - 2.55 = 1.43

Since, a B-F bond has the highest electronegativity difference. Therefore, $BF_{3}$ is the most ionic compound and $NF_{3}$ is the least ionic compound.

(c) Electronegativity value of Se = 2.55

Electronegativity value of Te = 2.1

Electronegativity value of Br = 2.96

Electronegativity value of F = 3.98

Electronegativity difference of a Se-F bond = 3.98 - 2.55 = 1.43

Electronegativity difference of a Te-F bond = 3.98 - 2.1 = 1.88

Electronegativity difference of a Br-F bond = 3.98 - 2.19 = 1.02

Since, a Te-F bond has the highest electronegativity difference. Therefore, $TeF_{4}$ is the most ionic compound and $BrF_{3}$ is the least ionic compound.

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3 years ago

Bonds between metals and nonmetals tend to be ionic, but bonds between nonmetal atoms tend to be covalent. Explain why this is t

Assoli18 [71]

Ionic bond is a type of bond in which one or more atoms are transferred to another atom which results to two ions with opposite charge. They attract each other.

The atom of another element is removed and then gained by another element which produces a noble gas electron configuration.

Covalent bond is a type of bond in which a pair or more electrons are being shared by the atoms of two elements.

Because of this, the molecules become stable by sharing the electrons thus creating a noble gas configuration for each of the atom.

3 0

3 years ago

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B. Each atom is neutrally charged, which means that each atom has the same number of protons and

vesna_86 [32]

Sodium has 11 protons and Chlorine has 17.

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2 years ago