1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OLEGan [10]
3 years ago
11

Calculate the volume, in ml. of the 1.0 m naoh stock solution needed to prepare 250 ml of 0.1 molar naoh.

Chemistry
1 answer:
Aneli [31]3 years ago
8 0
By using the following formula we can calculate the volume;
C₁V₁ = C₂V₂
C₁ = concentration of starting solution = 1.0m
V₁ = volume of starting solution that is needed to make the dilution = ?
C₂ = Desired concentration of final solution = 0.1m
V₂ = desired volume of final solution = 250ml
Now putting the values in the formula;
1 x V₁ = 0.1 x 250
V₁ = 25ml
Thus, the answer is 25ml.

You might be interested in
The half-life for the radioactive decay of calcium-47 is 4.5 days. how many half-lives have elapsed after 27 days?
Evgesh-ka [11]
1 half-life      - 4.5 days
x half-lives   - 27 days

x=(1*27)/4.5=6
6 <span>half-lives have elapsed after 27 days.</span>
8 0
4 years ago
Read 2 more answers
What happened to the FREQUENCY of the wave as the instrument got bigger?
Archy [21]

Answer:

The wavelengths at which resonance occurs are proportional to the length of the instrument, so you can play different notes by changing the length. In general the larger the instrument the longer the wavelength of the fundamental and the lower the frequency range of the instrument.

Explanation:

4 0
3 years ago
A balloon containing N2 has 1.70 moles and occupies 3.80L. What will the volume be if the number of moles is increased to 2.60mo
leonid [27]

Answer:

5.81L

Explanation:

N1 = 1.70 moles

V1 = 3.80L

V2 = ?

N2 = 2.60 moles

Mole - volume relationship,

N1 / V1 = N2 / V2

V2 = (N2 × V1) / N1

V2 = (2.60 × 3.80) / 1.70

V2 = 9.88 / 1.70

V2 = 5.81 L

The volume of the gas is 5.81L

8 0
3 years ago
An equation thats shows how an objects acceleration relates to its mass
Nady [450]

Answer:

Newton's second law of motion

F = ma

5 0
3 years ago
Potential energy due to the position of an object above earth surface is called
KengaRu [80]

ANSWER:

Potential energy due to the position of an object above Earth&#39;s surface is called gravitational  potential energy.

EXPLANATION:

Gravitational energy is the potential energy compared with gravitational force, as work is  needed to further things against Earth’s gravity. The potential energy due to high positions is  called gravitational potential energy, and is evidenced by water in an elevated storage or kept  behind a dam. If an article falls from one point to different point inside a gravitational field, the  force of gravitation will do actual work on the object, and the gravitational potential energy will  decrease by the same amount.

7 0
3 years ago
Other questions:
  • How does transcription work
    10·1 answer
  • Calculate the density, in g / mL , of a liquid that has a mass of 0.125 g and a volume of 0.000285 L
    14·1 answer
  • Name one object that would be considered a solid. Describe how the atoms move in a<br> solid object.
    10·1 answer
  • The reaction 2Fe + 3Br2 ———&gt; 2FeBr3 is an example of which type of reaction
    10·1 answer
  • 9 Which term represents the attraction one atom has for the electrons in a bond from another atom?
    10·1 answer
  • Can the element calcium be found in more than one state of matter?
    14·1 answer
  • What is the percentage yield if 125.4g C3H8 are collected from a reaction that should produce 157.4g C3h8?
    15·1 answer
  • Plant cells use photosynthesis to make food. ​Plant cells also use cellular respiration to get energy from the food they make. ​
    11·2 answers
  • What is the numerical value of gold silver and platinum?
    7·1 answer
  • When used as pure gases for welding ferrous metals, ____ may produce an erratic arc action, promote undercutting, and result in
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!