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Triss [41]
3 years ago
14

How many grams of a stock solution that is 87.0 percent H2SO4 by mass would be needed to make 200 grams of a 35.5 percent by mas

s solution? Show all of the work needed to solve this problem
Chemistry
1 answer:
Jet001 [13]3 years ago
5 0
Answer: Use c1(v1) = c2(v2) to solve<span> that </span>problem. 87%(200) = (35.5<span>%)v2 v2 ≈ 490.5. I hope this helps! Source(s)</span>
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Changing the volume increases the area that the molecules collide with so the force is spread over a larger area.

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Identify the property of the substance that is changing. A. composition B. volume C. boiling point
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Property of Volume changes.

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Match the following aqueous solutions with the appropriate letter from the column on the right.1. 0.19 m AgNO3 2. 0.17 m CrSO4 3
vichka [17]

Answer:

0.13 m of Mn(NO_3)_2 → Highest boiling point

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Explanation:

Elevation in boiling is given by :

\Delta T_b=i\times k_b\times m

Where :

i = van't Hoff factor

k_b= Molal Elevation constant of solvent

m = molaity of the solution

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i = 2 (electrolyte)

Molality of the solution = 0.19

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\Delta T_b=2\times k_b\times 0.19 m

\Delta T_b=0.38 m\times k_b

2) 0.17 m of CrSO_4

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\Delta T_b=2\times k_b\times 0.17 m

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3) 0.13 m of Mn(NO_3)_2

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\Delta T_b=3\times k_b\times 0.13 m

\Delta T_b=0.39 m\times k_b

4) 0.31 m Sucrose (nonelectrolyte)

i = 1 ( non electrolyte)

Molality of the solution = 0.31 m

Elevation is boiling point solution :

\Delta T_b=1\times k_b\times 0.31 m

\Delta T_b=0.31 m\times k_b

Higher the value of elevation in temperature higher will be the boiling point of the solution .

The decreasing order of solution from highest boiling point to lowest boiling point is :

0.39 m\times k_b>0.38 m\times k_b>0.34 m\times k_b>0.31 m\times k_b

0.13 m of Mn(NO_3)_2 → Highest boiling point

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6 0
3 years ago
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Keith_Richards [23]

Answer:

a - the position of equilibrium lies far to the right, with products being favored.

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