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3 years ago

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How many grams of a stock solution that is 87.0 percent H2SO4 by mass would be needed to make 200 grams of a 35.5 percent by mas

s solution? Show all of the work needed to solve this problem

1 answer:

Jet001 [13]3 years ago

5 0

Answer: Use c1(v1) = c2(v2) to solve<span> that </span>problem. 87%(200) = (35.5<span>%)v2 v2 ≈ 490.5. I hope this helps! Source(s)</span>

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How many liters of o2 do you have if you have 5.8 moles of o2

polet [3.4K]

Answer:

130 Liters

Explanation:

if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)

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3 years ago

Which of the following sets of empirícal formula, molar mass, and molecular formula is correct?

skad [1K]

<em>Answer:</em>

The option C is correct.
CH4N, 90g, C3H12N3.

<em>Explanation:</em>

<em>Option C:</em>

The molecular formula is C3H12N3.

If we take ratio 3:12:3 that will be equal to 1:4:1 so its empirical formula will be CH4N.
The molar mass of molecular formula = (12×3) + (1×12) +( 14×3) = 98 g

<em>Option A :</em>

In option A , molecular and empirical formula are both correct but molar mass is not valid. It should be 169 acc. to molecular formula.

<em>Option B:</em>

In option B, molecular formual is not valid.
It should be as C6H16O2

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3 years ago

A gas cylinder initially contains 463 L of gas at a pressure of 159 atm. If the final volume of gas is 817 L, what is the final

Agata [3.3K]

Answer:

The final pressure is 90.1 atm.

Explanation:

Assuming constant temperature, we can solve this problem by using <em>Boyle's Law</em>, which states:

P₁V₁=P₂V₂

Where in this case:

P₁ = 159 atm

V₁ = 463 L

P₂ = ?

V₂ = 817 L

We <u>input the given data</u>:

159 atm * 463 L = P₂ * 817 L

And <u>solve for P₂</u>:

P₂ = 90.1 atm

The final pressure is 90.1 atm.

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I KNOW THE ANS JUST NEED AN EXPLANATION...PLEASE I WILL Mark you the brainiest

Reika [66]

I’m pretty sure it would be D.

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Answer:

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