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Triss [41]
3 years ago
14

How many grams of a stock solution that is 87.0 percent H2SO4 by mass would be needed to make 200 grams of a 35.5 percent by mas

s solution? Show all of the work needed to solve this problem
Chemistry
1 answer:
Jet001 [13]3 years ago
5 0
Answer: Use c1(v1) = c2(v2) to solve<span> that </span>problem. 87%(200) = (35.5<span>%)v2 v2 ≈ 490.5. I hope this helps! Source(s)</span>
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the solubility of nitrogen gas is 1.90 mL/dL of blood at 1.00 atm. what is the solubility of nitrogen gas in a deepsea divers bl
leonid [27]

The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.

We want to relate the solubility of a gas with its partial pressure.

We can do so using Henry's law.

<h3>What does Henry's law state?</h3>

Henry's law states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid.

C = k × P

where,

  • C is the concentration of a dissolved gas.
  • k is the Henry's Law constant.
  • P partial pressure of the gas.

The solubility of nitrogen gas is 1.90 mL/dL of blood at 1.00 atm.

Since the solvent is basically water, we can understand that the concentration of nitrogen gas is 1.90 mL/dL at 1.00 atm.

We can use this information to calculate Henry's Law constant.

k = C/P = (1.90 mL/dL)/1.00 atm = 1.90 mL/dL.atm

We want to calculate the solubility of nitrogen gas at a pressure of 7.00 atm.

We will use Henry's law.

C = k × P = (1.90 mL/dL.atm) × 7.00 atm = 13.3 mL/dL

The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.

Learn more about solubility here: brainly.com/question/11963573

6 0
3 years ago
A sample of methane occupies a volume of 370.0 ml at 25 oC and exerts a pressure of 1020 mm Hg. If the volume is allowed to expa
vagabundo [1.1K]

Answer:

744.9 mmHg ≅ 745 mmHg

Explanation:

The base to solve this, is the Ideal Gases Law. The mentioned formula is:

P . V = n . R . T

To compare two situations, we can propose:

For the first situation P₁ . V₁ = n₁. R . T₁

For the second situation P₂ . V₂ = n₂ . R . T₂

As the sample has the same moles and R is a constant value, we can avoid them so: (P₁ . V₁) / T₁ = (P₂ . V₂) / T₂

We need to make Tº unit conversion:

25ºC + 273 = 298K

We replace data → (370 mL . 1020 mmHg) / 298K = (P . 510 mL) / 300 K

(377400 mL.mmHg / 298K) . 300 K = P . 510 mL

379932.8 mL . mmHg = P . 510 mL

(379932.8 mL . mmHg) / 510 mL = P → 744.9 mmHg

7 0
3 years ago
Which of the following statements are TRUE? Group of answer choices Dynamic equilibrium indicates that the amount of reactants a
White raven [17]

Answer:

Below answers are correct.

1) Dynamic equilibrium indicates that the amount of reactants and products are equal.

2) A reaction quotient (Q) larger than the equilibrium constant (K) means that the reaction will favor the production of more products.

3) Dynamic equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction

Explanation: Dynamic equilibrium is also called reversible reaction because it moves both in farward as well as in backward direction. Dynamic equilibrium occurs when reactants convert into products and products convert into reactant at the same time. It only occurs when the reaction occurs in closed container.

4 0
3 years ago
What is the volume of 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)?
uysha [10]
Given:
<span> 2.1 moles of chlorine gas (Cl2) at standard temperature and pressure (STP)
Required:
volume of CL2
Solution:
Use the ideal gas law
PV = nRT
V = nRT/P
V = (2.1 moles Cl2) (0.08203 L - atm / mol - K) (273K) / (1 atm)
V = 47 L</span>
5 0
3 years ago
True or false? You can follow the progress of a reaction that produces a gas using a sensitive mass
sasho [114]

Answer:

true

Explanation:

3 0
3 years ago
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