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-BARSIC- [3]
2 years ago
5

What type of heat transfer is used to fry an egg in a pan and how can you tell?

Physics
2 answers:
Deffense [45]2 years ago
6 0

Answer: Option (B) is the correct answer.

Explanation:

A process in which transfer of heat occurring when one object touches another object is known as conduction.  

For example, when a pan is heated and then an egg is placed over the pan. Then there will be transfer of heat from pan towards the egg.

As a result, the egg gets cooked because the egg was touching the pan.

Hence, we can conclude that it is conduction because the egg is touching the pan.

Scilla [17]2 years ago
6 0
The answer would be B. its is conduction because the egg is touching the pan. 
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How much energy, in Joules, is needed to raise the temperature from 25.87°C to 33.16°C in a 2.66 kg block of each of the followi
RUDIKE [14]

Answer:

(a) Silver, H = 455.67 J

(b) Iron, H = 870.67 J

(c) titanium, H = 1012.23 J

Explanation:

mass of block, m = 2.66 kg = 266 g

T1 = 25.87° C

T2 = 33.16° C

ΔT = T2 - T1 = 33.16 - 25.87 = 7.29° C

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The heat required is given by

H = m x c x ΔT

H = 266 x 0.235 x 7.29 = 455.67 J

(b) Specific heat of iron, c = 0.449 J/g K

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H = m x c x ΔT

H = 266 x 0.449 x 7.29 = 870.67 J

(c) Specific heat of titanium, c = 0.522 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.522 x 7.29 = 1012.23 J

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3 years ago
Physics Question 100 Points No Spam.
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A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
maksim [4K]

Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

  The first amplitude of the wave is  E_{max}1 =  98.02 \  V/m

  The first  depth  is  D_1 =  10 \  m

   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

   The second depth is D_2 = 100 \ m

Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

=>   \alpha  =  \frac{0.18}{90}

=>    \alpha =  0.002 Np/m

       

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3 years ago
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What is the function of the bronchioles?<br> please help
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Answer:

The bronchioles function is to deliver air to tiny sacs called alveoli where oxygen and carbon dioxide are exchanged.

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