Question

Which of the following has the greatest number of particles A) 1 mole of Na B)22.990g of Na C) 1 mole of Be D) 9.012 g of Be E) all are the same

Answer 1

Answer:

E) all are the same

Explanation:

The question requires we identify the amount of an element with the greatest number of particles.

• We need to know that 1 mole of an element contains particles equivalent to the Avogadro's number, 6.022 × 10^23.
• That is, 1 mole of an element = 6.022 × 10^23 particles

In this case;

Choice A

1 mole of Na

1 mole of Na contains 6.022 × 10^23 atoms

Choice B

22.990 g of Na

The molar mass of sodium is 22.99 g/mol

Therefore, 22.990 g of Na contains 6.022 × 10^23 atoms

Choice C

1 mole of Be

1 mole of Be contains 6.022 × 10^23 atoms

Choice D

9.012 g of Be

But, the molar mass of Be is 9.012 g

Thus; 9.012 g of Be contains 6.022 × 10^23 atoms

• We can therefore, conclude that all the given choices are the same, they have equal number of particles.

Answer 2

E) all are the same

Explanation:

Mole:

The mole(mol) is a unit of amount in chemistry. One mole of a substance refers to the mass of Avogadro's Number of particles of that substance. The number of particles in 12.00 g of Carbon(12) is called Avogadro's Number which is equal to 6.022 x 10²³.

A particle refers to an atom in case of an element or a molecule in case of a compound. Particles of different substance might vary in mass or size. Thus, equal number of particles of two different substances might have different masses in grams.

1 mole of Na has Avogadro Number of particles.

22.990 g of Na is equal to 1 mole of Na and has Avogadro Number of particles.

Similarly, 9.012 g of Be is also equal to 1 mole and has Avogadro Number of Be atoms.

Hence, the number of particles of all the three options are same.

Keyword: Avogadro Number

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