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3 years ago

Which of the following examples of energy can be both Potential Energy and Kinetic Energy?

Chemistry

2 answers:

likoan [24]3 years ago

7 0

It’s B chemical energy

omeli [17]3 years ago

3 0

It’s B or D sorry if wrong

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Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.

denpristay [2]

Answer:

For a: The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b: The mass of methane gas produced will be 10.384 g.

Explanation:

For the given chemical reaction:

$2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ$

For a:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

$\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol$

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = $\frac{252.8}{2}\times 0.749=94.6736kJ$

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b:

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = $\frac{2}{252.8}\times 82.1=0.649mol$ of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

$0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g$

Hence, the mass of methane gas produced will be 10.384 g.

7 0

4 years ago

What is the change in enthalpy for the following reaction?

Tju [1.3M]

The given chemical reaction is:

$2H_{2}O_{2}(aq)---> 2H_{2}O(l)+O_{2}(g)$

The standard heats of formation of $H_{2}O and H_{2}O_{2}$ are:

Δ $H_{f}^{0}(H_{2}O$ ) = -285.8kJ/mol[/tex]

Δ $H_{f}^{0}(H_{2}O_{2}$ ) = -187.6 kJ/mol[/tex]

Calculating the change in heat:

Δ $H^{0}_{reaction)$ =∑ΔH $_{f}^{0}(products)$ -∑ΔH $_{f}^{0}(reactants)$

= [{2 * (-285.8 kJ/mol)} -{2*(-187.6 kJ/mol)}]

= -196.4 kJ/mol

Therefore, the change in enthalpy for the given reaction is -196.4 kJ/mol

7 0

3 years ago

Why is physical exercise often suggested if you experience an abundance of stress?

scoray [572]

Answer:

good question

Explanation:

probably because people like to say they know things and help people with "there stress" and think that there helping them but in reality there making it where they have more :)

4 0

3 years ago

1. Quando absorvido pelos pulmões, o monóxido de carbono reduz a habilidade do sangue no transporte do oxigênio pelo corpo. Este

Hoochie [10]

Perdon no te entiendo

3 0

3 years ago

If the mass of a material is 75 grams and the volume of the material is 16 cm3, what would the density of the material be?

qwelly [4]

P=75/16=4.6875 g/cm³

7 0

4 years ago

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