Answer:
6.82 moles of Fe2O3
Explanation:
Step 1:
Determination of the number of mole of in 450g of CO2.
This is illustrated below:
Molar Mass of CO2 = 12 + (2x16) = 44g/mol
Mass of CO2 = 450g
Number of mole of CO2 =.?
Number of mole = Mass/Molar Mass
Number of mole of CO2 = 450/44 = 10.23 moles
Step 2:
Determination of the number of mole of Fe2O3 needed for the reaction. This is illustrated below:
2Fe2O3 + 3C—> 4Fe + 3CO2
From the balanced equation above,
2 moles of Fe2O3 reacted to produce 3 moles of CO2.
Therefore, Xmol of Fe2O3 will react to produce 10.23 moles of CO2 i.e
Xmol of Fe2O3 = (2x10.23)/3
Xmol of Fe2O3 = 6.82 moles
Therefore, 6.82 moles of Fe2O3 is required.
A fish is a living thing and a rock is not
<span>2 Na + CaF</span>₂<span> = 2 NaF + Ca
is an example of a </span>single- replacement
answer D
hope this helps!
This is the complete question with grammar corrections:
A glass vessel calibrated to contain 9.76 mL at 4° C was found to weigh 22.624 g when empty and dry. Filled with a soduim chloride (NaCl) solution at the same temperature , it was found to weigh 32.770 g. Calculate the solution's density.
Answer:
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Explanation:
<em>Density</em> is the physical property that expresses the amount of matter (mass) per voumetric unit of solution:
In this problem, you can first calculate the mass, by difference. After that, you just have to divide the mass by the volume of the glass vessel (9.76 ml as per the calibration).
This is the two steps procedure.
<u>1. Mass of the solution:</u>
- Mass of solution = mass of the vessel filled with the solution - mass of the vessel, empty and dry
Mass of solution = 32.770 g - 22.624 g = 10.146 g
<u>2. </u><em><u>Solution's density</u></em><u>:</u>
- density = mass / volume = 10.146 g / 9.76 ml = 1.0395 g / ml ≈ 1.04 g/ml
The density is rounded to 3 significant digits because the volume, which is dividing the mass, was reported with 3 significant digits.
Answer:
The reflection of sound waves
Explanation:
An echo is a reflection of sound that bounces of of one thing to another.
