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2 years ago

The temperature of 335 g of water changed from 24.5oC to 26.4oC. How much heat did this sample absorb? C for water = 4.18 J/goC

Chemistry

1 answer:

Sergio039 [100]2 years ago

8 0

Answer: The sample absorbed 3061.565J

Explanation:

Given that

Mass of water = 335g

Initial temperature = 24.5°C

Final temperature = 26.4°C

Heat absorbed by the sample is given as = mass x specific heat of water x temperature change

Heat absorbed,q=mCΔt

The specific heat of water,C = 4.81J/g°C

Therefore, Heat absorbed,q = 335 x 4.81h x (26.4 - 24.5) = 3061.565J

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