Question

The temperature of 335 g of water changed from 24.5oC to 26.4oC. How much heat did this sample absorb? C for water = 4.18 J/goC

Answer 1

Answer: The sample absorbed 3061.565J

Explanation:

Given that  

Mass of water  = 335g

Initial temperature  = 24.5°C

Final temperature = 26.4°C

Heat  absorbed by the sample is given as  = mass x specific heat of water x  temperature change

Heat  absorbed,q=mCΔt

The specific heat of water,C  = 4.81J/g°C

 

Therefore,  Heat absorbed,q  = 335 x 4.81h x (26.4  - 24.5)  = 3061.565J