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Nikitich [7]
3 years ago
8

Hydrogenation of poly(butadiene) converts both cis and trans isomers to the same linear structure, and vinyl groups to ethyl bra

nches. A poly(butadiene) sample of molecular weight 168,000 g/mol was found by infrared spectroscopy to contain double bonds consisting of 47.2% cis, 44.9% trans, and 7.9% vinyl.
After hydrogenation, what is the average number of backbone carbon atoms between ethyl side chains?

Chemistry
1 answer:
Alexeev081 [22]3 years ago
7 0

Answer:

The average number is given as 48.6

Explanation:

From the question we see that the

                    Percentage of cis = 47.2%

                    Percentage of trans = 44.9%

                    Percentage of  vinyl = 7.9%

The chemical  reaction equation for the hydrogenation of polybutadiene is shown on the first uploaded image

    To obtain the average number of  backbone carbon between the ethyl side chains ,we divide the total number of carbon on the backbone by the total number of ethyl group

              That is

                             = (44.9% × 4 + 47.2% ×4 + 7.9% × 2) ÷(7.9% × 1)

                             = (384.2%/7.7%)

                              = 48.6

Note :  The percentage will cancel out

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svetoff [14.1K]

Answer:

A negatron emission

Explanation:

We know that radioactivity orginates from instability of the nucleus. When the nucleus is unstable, radioactive emissions are produced in the form of any of these rays:

> Alpha particle emisson

>Beta particles

> Gamma rays

These emissions create a balance for a radioactive decay.

In balancing nuclear reactions we make sure that the charges on both sides must be conserved and that the mass number and atomic numbers conserved too. This means that the sum of mass number and atomic numbers on both side of the reaction must be equal.

The nucleons are the protons and neutrons, they add up to give the mass number. The atomic number is the proton number.

For the given radioactive reaction:

²³¹₉₀Th → ²³¹₉₁Pa + ?

From this equation, we see that the mass number is conserved but the atomic number is not.

The mass number is the superscript whereas the atomic number is the subscript.

Let's say the decay produces an emission of a particle denoted by X

²³¹₉₀Th → ²³¹₉₁Pa + ᵃₙX

What would the nature of X be?

For the charges and masses to be conserved, X must have mass number of 0 and an atomic number of -1.

Checking:

Mass number:

231 = 231 + a ( a is the mass number)

a = 231 - 231 = 0

Atomic number:

90 = 91 + n

n = 90- 91 = - 1

With X having a mass number of 0 and an atomic number of -1, we have a beta particle emission. Specifically, a negatron has been emitted.

A negatron is denoted as ⁰₋₁β which perfectly makes the equation conserved and suits the description of X.

The complete equation is thus written as:

²³¹₉₀Th → ²³¹₉₁Pa + ⁰₋₁β + energy

6 0
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Write each mixed number as as a decimal. Use bar notation if the decimal is repeating.
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4 0
2 years ago
An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0
3 years ago
A molecule that oxidized gains electrons and energy. true or false
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I suppose it false, since the oxidation involves the loss or removal of the electrons such forth it does not gain electrons.
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