I did it on the calculator and the answer is 7.77777777778
Answer:
Inequality
Step-by-step explanation:
There are an infinite number of quantities less than 6 (5, 4, 3, 2, 1, 0, -1, -2, -3...) so it is much easier to write an inequality
Answer:
C. The rudely disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the politely disagrees condition has a mean of 3.82 and standard deviation of 0.97
Step-by-step explanation:
The given data is
x` Std. Dev
R. disagrees 4.16 0.854
P. disagrees 3.82 0.967
From this data we see that the R. disagrees has a mean of 4.16 and standard deviation of 0.854
while
the P. disagrees has a mean of 3.82 and standard deviation of 0.967.
Same figures are given only in option C because
Rounding 0.854 gives 0.85
Rounding 0.967 gives 0.97
So only option C is the best choice.
C. The R. Disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the P. Disagrees condition has a mean of 3.82 and standard deviation of 0.97
Answer:
Step-by-step explanation:
9x⁴ – 2x² – 7 = 0
Let's say that u = x²:
9u² – 2u – 7 = 0
Factor:
(u – 1) (9u + 7) = 0
u = 1, -7/9
Since u = x²:
x² = 1, -7/9
x = ±1, ±i √(7/9)
Answer:

Step-by-step explanation:

Apply formula:
and

We get:







Hence final answer is
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