Answer:
<em>b. The current in the loop always flows in a counterclockwise direction.</em>
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Explanation:
When a magnet falls through a loop of wire, it induces an induced current on the loop of wire. This induced current is due to the motion of the magnet through the loop, which cause a change in the flux linkage of the magnet. According to Lenz law, the induced current acts in such a way as to repel the force or action that produces it. For this magnet, the only opposition possible is to stop its fall by inducing a like pole on the wire loop to repel its motion down. An induced current that flows counterclockwise in the wire loop has a polarity that is equivalent to a north pole on a magnet, and this will try to repel the motion of the magnet through the coil. Also, when the magnet goes pass the wire loop, this induced north pole will try to attract the south end of the magnet, all in a bid to stop its motion downwards.
Answer:
gravitational acceleration is the acceleration of an object in free fall within a vacuum (and thus without experiencing drag). This is the steady gain in speed caused exclusively by the force of gravitational attraction.
Given: Radius of the Moon Rm = 1.74 x 10⁶ m
Mass of the Moon Mm = 7.35 X 10²² Kg
Universal Gravitational constant G = 6.67 X 10⁻¹¹ N.m²/Kg²
Required: acceleration due to gravity g = ?
Formula: g = GMm/Re²
g = (6.67 x 10⁻¹¹ N.m²/Kg²)(7.35 x 10²² Kg/(1.74 x 10⁶ m)²
g = 4.90 x 10¹² N.m²/Kg/3.0 x 10¹² m²
g = 1.63 m/s²
Part 1: V = gt = 10(11) = 110 m/s
Part 2: Vavg = V/2 = 110/2 = 55 m/s
Part 3: d = Vavg(t) = 55(11) = 605 m
Answer:
Mu,k between the floor and the box is 0.609
Explanation:
given information:
weight of the book, W = 325 N
applied force, F = 425 N
angle, θ = 35.2°
to find the coefficient kinetic between the floor and the box, wee need to calculate the horizontal and vertical force.
first we calculate the vertical force, there are weight, normal force(N) and applied vertical force.
according to Newton's first law
ΣF = 0
Σ
= 0
W - N + F sin θ = 0
N = W + F sin θ
Next, we calculate the force in horizontal direction. applied force and friction force(
)
Σ
= 0
F cos θ - = 0
F cos θ - μk (W - F sin θ) = 0
μk = (F cos θ) / (W + F sin θ)
= (425 cos 35.2°)/(325+425 sin 35.2°)
= 0.609
