Complete question:
A block of solid lead sits on a flat, level surface. Lead has a density of 1.13 x 104 kg/m3. The mass of the block is 20.0 kg. The amount of surface area of the block in contact with the surface is 2.03*10^-2*m2, What is the average pressure (in Pa) exerted on the surface by the block? Pa
Answer:
The average pressure exerted on the surface by the block is 9655.17 Pa
Explanation:
Given;
density of the lead, ρ = 1.13 x 10⁴ kg/m³
mass of the lead block, m = 20 kg
surface area of the area of the block, A = 2.03 x 10⁻² m²
Determine the force exerted on the surface by the block due to its weight;
F = mg
F = 20 x 9.8
F = 196 N
Determine the pressure exerted on the surface by the block
P = F / A
where;
P is the pressure
P = 196 / (2.03 x 10⁻²)
P = 9655.17 N/m²
P = 9655.17 Pa
Therefore, the average pressure exerted on the surface by the block is 9655.17 Pa
Answer:
The first law states that if the net force is zero, then the velocity of the object is constant.
Earth's gravity pulls air as close to the surface as possible. As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level.
Answer:
Explanation: I think...
Thermal Energy formula Q = mcΔT
Q = Thermal Energy(J)
m = Mass(kg)
c = Specific Heat(J/kg°C)
ΔT = Change in Temperature(°C)
you have to write the equation based on what you are working on
