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Answer: The four hybridized orbitals on Sb makes up the sigma bonds between Sb and F in antimony(iii) fluoride ,
Explanation:
According to VESPR theory:
Number of electrons around the central atom :
V = number of valence electrons
N = number of neighboring atoms
C = charge on cation
A = charge on an anion
In antimony(III) fluoride ,
Antimony being central atom: V= 5,N =3,C=0,A=0
Number of electrons :
Number of electrons around the central atom are 4 which means that molecule has four
hybridized orbitals.
The question is incomplete, the complete question is:
Nitrogen and fluorine react to form nitrogen fluoride according to the chemical equation:
A sample contains 19.3 g of is reacted with 19.3 g of
. Now we need to find the amount of
that can be formed by the complete reactions of each of the reactants.
If all of the was used up in the reaction, how many moles of
would be produced?
<u>Answer:</u> 1.378 moles of are produced in the reaction.
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
......(1)
Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.
Excess reagent is defined as the reagent which is left behind after the completion of the reaction.
In the given chemical reaction, is considered as a limiting reagent because it limits the formation of the product and it was completely consumed in the reaction.
We are given:
Mass of = 19.3 g
Molar mass of = 28.02 g/mol
Putting values in equation 1:
For the given chemical reaction:
By the stoichiometry of the reaction:
1 mole of produces 2 moles of
So, 0.689 moles of will produce =
of
Hence, 1.378 moles of are produced in the reaction.