1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nikitich [7]
4 years ago
14

The current supplied by a battery as a function of time is What is the total number of electrons transported from the positive e

lectrode to the negative electrode from the time the battery is first used until it is essentially dead? (e = 1.60 × 10-19 C)
Physics
1 answer:
OLEGan [10]4 years ago
5 0

Complete Question

The current supplied by a battery as a function of time is I(t) = (0.88 A) e^(-(t * 6 hr)). What is the total number of electrons transported from the positive electrode to the negative electrode from the time the battery is first used until it is essentially dead?

Answer:

The total number of electrons transported is n=2.54*10^{14}\ electrons

Explanation:

Charge is generally expressed as

           q = \int\limits^{\infty}_0 {I} \, dt

Where I is the current and it is given as

         I = (0.88A) e^{{ -t *6 hr} } = (0.88A) e^{-21600t} }

Substituting into equation above d

        q = \int\limits^{\infty}_0 {0.88 e^{-21600t}} \, dt

           q = 0.88[-\frac{e^{-21600t}}{21600} ]\left \ {{\infty} \atop {0}} \right.

          q = - \frac{0.88}{21600} [-1]

           q = 4.074*10^{-5}C

   This charge can also be expressed as

            q = n *e

Where is the number of electron

Making n the subject

             n = \frac{q}{e}

                = \frac{4.074*10^{-5}}{1.60*10^{-19}}

               =2.54*10^{14}\ electrons

You might be interested in
A positively-charged object with a mass of 0.129 kg oscillates at the end of a spring, generating ELF (extremely low frequency)
9966 [12]

Answer:308 N/m

Explanation:

Given

mass\left ( m\right )=0.129 kg

wavelength\left ( \lambda \right )=3.86\times 10^7

We know frequency =\frac{c}{\lambda }=\frac{3\times 10^8}{3.86\tmes 10^7}

f=7.772 Hz

As the frequency of radio waves is same as the frequency at which object oscillates

f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

7.772=\frac{1}{2\pi }\sqrt{\frac{k}{0.129}}

7.772\times 2\times \pi =\sqrt{\frac{k}{0.129}}

k=307.70\approx 308 N/m

7 0
4 years ago
The system below has a friction force of 25 N acting on the cart which 8 kg. The mass hanging off the edge has a mass of 6 kg. F
photoshop1234 [79]

The cart will be pulled to the right by the hanging mass, so by Newton's second law, the net force on the cart is

<em>T</em> - 25 N = (8 kg) <em>a</em>

where <em>T</em> is the tension in the rope and <em>a</em> is the acceleration.

The hanging mass has a net force of

(6 kg) <em>g</em> - <em>T</em> = (6 kg) <em>a</em>

where <em>g</em> = 9.8 m/s².

Adding these equations together eliminates <em>T</em>, and we can solve for <em>a</em> :

(<em>T</em> - 25 N) + ((6 kg) <em>g</em> - <em>T </em>) = (14 kg) <em>a</em>

33.8 N = (14 kg) <em>a</em>

<em>a</em> = (33.8 N) / (14 kg) ≈ 2.4 m/s²

Then the tension in the rope is

<em>T</em> - 25 N = (8 kg) (2.4 m/s²)

<em>T</em> ≈ 25 N + 19.31 N ≈ 44 N

5 0
3 years ago
What is the frequency of a wave
MAVERICK [17]
The frequency of a wave is the number of waves that passes through a point in a certain time. The less waves that pass in a period of time the lower the frequency of the wave. The more waves that pass in a period of time the higher the frequency of the wave. When measuring wave length the time period used is usually one second.
6 0
3 years ago
Read 2 more answers
Given a second class lever with a distance of 5.00 feet from the fulcrum to the effort and a distance of 33.0 inches from the re
leva [86]

Answer:

The correct answer is C. 45.5 lbs.

Explanation:

In a second class lever, the load is located between the point in which the force is exerted and the fulcrum.

The formula for any problem involving a lever is:

F_ed_e=F_ld_l

Where F_e is the effort force, d_e is the total length of the lever, F_l is the load that can be lifted and d_l is the distance between the point of the effort and the fulcrum.

The parameter of the formula that you need is F_l:

F_l=\frac{F_ed_e}{d_l}

The conversion from feet to inches is 1 ft is equal to 12 inches. In this case, 5 ft are equal to 60 inches.

F_l=\frac{25*60}{33}

F_l=45.5 lbs

7 0
4 years ago
A viscous liquid of constant density 500 kg/m3 and viscosity 10 Pa s falls down with constant velocity due to gravity in a long
Alekssandra [29.7K]

Answer:

\tau=2452.5 N/m^2

Explanation:

given:

density \rho=500kg/m^3

viscosity \mu= 10 Pa-s

diameter of tube= 2 m

and L be length

since gravity is the only force shear force will balance it

so we can write

mg= \tau\times A

A=  \rho\times\frac{\pi}{4} d^2\times L

m=  \rho\times\frac{\pi}{4} d^2\times L

therefore

\rho\times\frac{\pi}{4} d^2\times Lg= \tau\times{\pi} d\times L

putting values we get

\ 500\times\frac{\pi}{4} 2^2\times g= \tau\times{\pi}\times 2

calculating we get \tau=2452.5 N/m^2

6 0
4 years ago
Other questions:
  • 1.<br> Distinguish between amplitude and frequency and give an example.
    5·1 answer
  • COMPA<br>WE APPLIANCE<br>NO STABILIZER<br>REQUIRED<br>* For 160V-260V power supply​
    12·1 answer
  • What is the net force needed to lift a full grocery sack weighing 210N uniformly?
    11·1 answer
  • What is the acceleration of a baseball when it is moving downward after being tossed directly upward?
    10·1 answer
  • what is the mass of an object that is moving at an acceleration of 25 m/s squared with a force of 20 N
    13·1 answer
  • Can someone help me?
    7·1 answer
  • A roller coaster car with a mass of 17,690 kg is moving at a speed of 5 m/s over a hill that is 87.4 m above the
    13·1 answer
  • You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 13-m-hi
    9·1 answer
  • What machine would benefit from slowing lights speed
    12·1 answer
  • An electric pole shown in the figure below supports a power line that passes through it. A cable tied to the pole at B passes th
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!