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aliina [53]
4 years ago
11

When a circuit has a supermesh, you write two equations: the supermesh constraint equation and the supermesh KVL equation. You h

ave completed this task. To complete the description of this circuit, two more equations are required, one of which is the KVL equation for the mesh whose current is iziz. Write this KVL equation.

Engineering
1 answer:
givi [52]4 years ago
3 0

Explanation:

Note: Refer the diagram attached

Apply KVL around i_{z} loop

\begin{aligned}&5 k \left(i_{z}-i_{y}\right)+2 v_{\Delta}=0\\&5000\left(i_{z}-i_{y}\right)+2 v_{\Delta}=0 \quad \ldots \ldots(1)\end{aligned}

From the circuit, \(v_{\Delta}\) can be expressed using ohm's law as,\\\(v_{\Delta}=(1 k ) i_{y}\)\(v_{\Delta}=1000 i_{y}\)

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Answer:

The maximum water pressure at the discharge of the pump (exit) = 496 kPa

Explanation:

The equation expressing the relationship of the power input of a pump can be computed as:

E _{pump,u} = \dfrac{m(P_2-P_1)}{\rho}

where;

m = mass flow rate = 120 kg/min

the pressure at the inlet P_1 = 96 kPa

the pressure at the exit P_2 = ???

the pressure \rho = 1000 kg/m³

∴

0.8 \times 10^{3} \ W = \dfrac{(120 \ kg/min * 1min/60 s)(P_2-96000)}{1000}

0.8 \times 10^{3}\times 1000 = {(120 \ kg/min * 1min/60 s)(P_2-96000)}

800000 = {(120 \ kg/min * 1min/60 s)(P_2-96000)}

\dfrac{800000}{2} = P_2-96000

400000 = P₂ - 96000

400000 +  96000 = P₂

P₂ = 496000 Pa

P₂ = 496 kPa

Thus, the maximum water pressure at the discharge of the pump (exit) = 496 kPa

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A system consists of N very weakly interacting particles at a temperature T sufficiently high so that classical statistical mech
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