Answer:
Mass percent N₂ = 89%
Mass percent H₂ = 11%
Explanation:
First we <u>use PV=nRT to calculate n</u>, which is the total number of moles of nitrogen and hydrogen:
- 1.03 atm * 7.45 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305 K
So now we know that
- MolH₂ + MolN₂ = 0.307 mol
and
- MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49 g
So we have a <u>system of two equations and two unknowns</u>. We use algebra to solve it:
Express MolH₂ in terms of MolN₂:
- MolH₂ + MolN₂ = 0.307 mol
Replace that value in the second equation:
- MolH₂ * 2 g/mol + MolN₂ * 28 g/mol = 3.49
- (0.307-MolN₂) * 2 + MolN₂ * 28 = 3.49
- 0.614 - 2MolN₂ + 28molN₂ = 3.49
Now we calculate MolH₂:
- MolH₂ + MolN₂ = 0.307 mol
Finally, we convert each of those mol numbers to mass, to <u>calculate the mass percent</u>:
- N₂ ⇒ 0.111 mol * 28 g/mol = 3.108 g N₂
- H₂ ⇒ 0.196 mol * 2 g/mol = 0.392 g H₂
Mass % N₂ = 3.108/3.49 * 100% = 89.05% ≅ 89%
Mass % H₂ = 0.392/3.49 * 100% = 11.15% ≅ 11%
In the Lewis symbol for a fluorine atom, there are <u>4</u> paired and <u>1</u> unpaired electrons.
However, paired electrons simply means are 2 electrons occupying the same orbital in an atom or molecule of a substance
On the other end, unpaired electron is a single electron that occupies an orbital of an atom.
<h3>What is an atom?</h3>
An atom is the smallest part of an element which can take part in a chemical reaction.
Some atoms of elements are:
- Monoatomic
- Diatomic
- Triatomic
- Polyatomic
In conclusion, in the Lewis symbol for a fluorine atom, there are 4 paired and 1 unpaired electrons.
Learn more about paired and unpaired electrons:
brainly.com/question/7457518
Answer:
In computer science, a literal is a notation for representing a fixed value in source code. An anonymous function is a literal for the function type. In contrast to literals, variables or constants are symbols that can take on one of a class of fixed values, the constant being constrained not to change.
Explanation:
The bond order of Mg2 molecule is given by:
Mg2 = 4e⁻= 3σs(2e⁻) 3σs*(2e⁻) 3σp(0) 3πp(0e⁻) 3πp*(0e⁻)
3σp*(0e⁻)
Bond Order = ½[Σ (bonding e-) - Σ (antibonding e-)]
bo = ½[ {σs(2e⁻)} - {σs*(2e⁻)}] = 0
the bond between Mg2 molecules are ionic bonding and it
stable.