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mr_godi [17]
3 years ago
6

What is it? Please help me.

Physics
1 answer:
Fed [463]3 years ago
4 0
I believe that is a
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Words that describe direction east, up, and left is it true or false
m_a_m_a [10]

Answer:

True

Explanation:

East, up, and left all define as a direction.

7 0
3 years ago
A locomotive approaches its next stop and accelerates at -0.12 m/s^2, coming to a complete stop in 30 seconds. This motion could
Masja [62]

Answer:

<em>Answer: positive velocity & negative acceleration</em>

Explanation:

<u>Accelerated Motion</u>

Both the velocity and acceleration are vectors because they have magnitude and direction. When the motion is restricted to one dimension, i.e. left-right or up-down, the direction is marked with the sign according to some preset reference.

The locomotive is moving at a certain speed with a (so far) unknown sign but the acceleration has a negative sign. Since the locomotive comes to a complete stop it means the velocity and the acceleration are of opposite signs.

Thus the velocity is positive.

Answer: positive velocity & negative acceleration

4 0
2 years ago
When you stand outside your are standing in the, Stratosphere. Troposphere. Mesosphere no
AVprozaik [17]
Uhhh I’m not really sure of the answer i think it’s stratosphere
8 0
3 years ago
Find the horizontal component and the vertical component ​
aleksandr82 [10.1K]

Answer:

v=3.66,h-3.66

Explanation:

vertical = 10sin60 - 10sin 30

horizontal =10cos60 + 10cos 30

v = 10×0.8660-10×0.5

h = 10×0.5 + 10 × 0.8660

v=8.660-5.0 = 3.66

h= 5.0-8.660 = -3.66

8 0
2 years ago
A scientist makes a device to catch baseballs. A long bar of total mass 2.2kg and length 1.2m is fixed at its center. It catches
Valentin [98]

Answer:

ωf = 4.53 rad/s

Explanation:

By conservation of the angular momentum:

Ib*ωb = (Ib + Ic)*ωf

Where

Ib is the inertia of the ball

ωb is the initial angular velocity of the ball

Ic is the inertia of the catcher

ωf is the final angular velocity of the system

We need to calculate first Ib, Ic, ωb:

Ib = mb*(L/2)^2=0.15*(1.2/2)^2=0.054 kg.m^2

Ic = mc/12*L^2=2.2/12*1.2^2=0.264 kg.m^2

ωb = Vb / (L/2) = 16 / (1.2/2) = 26.67 m/s

Now, ωf will be:

\omega f = \frac{Ib*\omega b}{Ib + Ic}  = 4.53rad/s

8 0
2 years ago
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