Answer:
a = - 0.3376 g's
Explanation:
The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s
It brakes and now comes to a stop in 3.6 s.
Thus final velocity = 0 m/s
Formula for acceleration is;
a = (v - u)/t
a = (0 - (164/13.77))/3.6
a = -3.308 m/s²
In terms of g's", where 1.00 g = 9.80 m/s², we have;
a = -3.308/9.8 g's
a = - 0.3376 g's
Answer:
v = K √(E / ρ)
Explanation:
Modulus of elasticity has units of N/m², or kg/m/s².
Density has units of kg/m³.
Velocity has units of m/s.
If we divide modulus of elasticity by density, we can eliminate kg:
E / ρ = [kg/m/s²] / [kg/m³]
E / ρ = [m²/s²]
Taking the square root gets us units of velocity:
√(E / ρ) = [m/s]
Multiply by the constant K:
v = K √(E / ρ)
The velocity of the wave on the string is given by
Solving the above equation,
The frequency of the wave 
and wave length is 
The velocity is 
Substituting numerical values,
The length of the string is 
