Answer:
0.85 mol/L.
Explanation:
- Molarity is defined as the no. of moles of solute dissolved in a liter of the solution.
<em>M = (no. of moles of solute)/(Volume of the solution (L))</em>
no. of moles of calcium phosphate = 2.125 mol.
Volume of the solution = 2.5 L.
<em>∴ M of calcium phosphate</em> = (2.125 mol)/(2.5 L) = <em>0.85 mol/L.</em>
Gibb free energy of activation is = -RT in K
R= gas constant=8.314 j/mol
T=temperature= 500+273= 773 K
K=rate constant
gibb free energy is therefore= - 8.314 j/mol /k x 773k in 5.95 x10^-4= 471730.94j/mol
Answer : 21.12 g
explanation :
- A limiting reactant is the substance that is totally consumed when the chemical reaction is complete and the reaction cannot continue without it.
- This is a limiting reactant problem because the amount of product (CO2) formed is limited by this substance (either O2 or C3H8).
- We can predict the limiting reactant by calculating number of mole for all reactants;
n (C3H8) = mass/ molar mass = 7/[(12 × 3)+(1 ×8)] = 0.16 mol
n (O2) = mass/ molar mass = 98/(16 × 2) = 3 mol
But we know from this balanced equation that for the reaction to continue, for (n) of propane there must be (5n) of oxygen. Clearly we have more oxygen than required for the reaction to continue as
[ 3 O2 mol > (0.16 propane mol × 5) . Hence, the limiting reactant is propane.
- Using cross multiplication,
0.16 mol propane → 1 mol propane
? → 3 mol CO2
So (n) of CO2 produced = 0.16 × 3 / 1 = 0.48 mol ,
And mass of CO2 produced = n × molar mass = 0.48 × [12 + (16 ×2)] = 21.12 g..
Here's a chart that will help you color in the periodic table for #20:
La gasolina es Contaminada