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Sholpan [36]
3 years ago
12

Given the following equation: 2C6H6 + 1502 - 12CO2 + 6H20

Chemistry
1 answer:
Margarita [4]3 years ago
5 0

Answer:

a) 30 moles

Explanation:

                           2C6H6 + 1502 -------> 12CO2 + 6H20

from reaction      2 mol       15 mol

given                    4.0 mol     x mol

x = 4.0*15/2 = 30. mol

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What do agents such as chemicals, elevated temperatures, ionizing radiation, and viruses have in common?
Leni [432]

Answer:

All of them affect the DNA

Explanation:

Chemicals are compounds that can pass through cell membranes and modificate the DNA, elevated temperatures can denaturalize the cell and therefore damage the DNA, ionizing radiation can pass through cell organelles and reach the nucleus affecting the DNA, and viruses inject its DNA into the genome and modify it.

4 0
3 years ago
7th grade SCIENCE PLEASE HELP ​
Flura [38]

Answer:  the first one is adaptation, third is migration, 4th is hibernation,

Explanation:

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4 0
3 years ago
A sample of C3H8 has 6.72 x 10^24 H atoms. <br> What is the total mass of the sample?
gregori [183]
The answer is 492.8 g


1. Calculate a number of moles of a sample.
2. Calculate a molar mass of C3H8.
3. Calculate a mass of the sample. 

1. Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance: 6.023 × 10²³ units per 1 mole    

6.023 × 10²³ atoms : 1 mol =6.72 × 10²⁴ atoms : n

n = 6.72 × 10²⁴ atoms * 1 mol : 6.023 × 10²³ atoms = 1.12 × 10 mol = 11.2 mol


2. Molar mass (Mr) of C3H8 is sum of atomic masses (Ar) of its elements:

Ar(C) = 12 g/mol

Ar(H) = 1 g/mol

Mr(C3H8) = 3 * Ar(C) + 8 * Ar(H) = 3 * 12 + 8 * 1 = 36 + 8 = 44 g/mol



3. Mass (m) of a sample is number of moles (n) multiplied by molar mass (Mr) of C3H8:

m = n * Mr = 11.2 mol * 44 g/mol = 492.8 g

6 0
3 years ago
What are standards or attributes of a design that can be measured.
ankoles [38]

Explanation:

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4 0
3 years ago
Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:
ankoles [38]
DeltaH formation = deltaH of broken bonds - deltaH of formed bonds

Broken bonds: tiple bond N-N and H-H bond
Formed bonds: N-H and N-N bonds

You also have to take note of the molar coefficients

deltaH formation = <span> [(N≡N) + 2 * (H-H)] - [4 * (N-H) + (N-N)] 
                           = (945 + 2*436) - (4*390 + 240)
                            = 17 kJ/mol

The answer is 17 kJ/mol.</span>
8 0
4 years ago
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