Cora, an electrician, wraps a copper wire with a thick plastic coating. What is she most likely trying to do?.

Use the balanced equation given below to solve the problem that follows: Calculate the mass in grams of water produced along wit

saveliy_v [14]

Answer: 1.98 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}$

$\text{Moles of} CO_2=\frac{5.0L}{22.4L}=0.22moles$

The balanced given equation is:

$C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)$

According to stoichiometry :

4 moles of $CO_2$ will produce = 2 moles of $H_2O$

Thus 0.22 moles of $CO_2$ will produce= $\frac{2}{4}\times 0.22=0.11moles$ of $H_2O$

Mass of $H_2O=moles\times {\text {Molar mass}}=0.11moles\times 18g/mol=1.98g$

Thus 1.98 g of water is produced along with 5.0 L of $CO_2$ at STP

6 0

3 years ago

Stoichionetry Quiz

Maru [420]

Answer:

a

Explanation:

first form your equation and it is C3H8+5O2-4H2O+3CO2 44g of C3H8 produce 3moles of CO2/400g of C3H8 produce x the answer is 27.27moles when you cross multiply

4 0

3 years ago

Please balance the equation, putting the correct coefficient in each box.

Mariulka [41]

Answer: $Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced equation will be:

$Bi(OH)_3+3HNO_3\rightarrow 3H_2O+Bi(NO_3)_3$

5 0

3 years ago

Be sure to answer all parts. Dimercaprol (HSCH2CHSHCH2OH) was developed during World War I as an antidote to arsenic-based poiso

Sauron [17]

Answer:

For A: The number of arsenic atoms are $3.4\times 10^{21}$

For B: The percent composition of mercury, thallium and chromium in their complexes are 61.76 %, 62.2 % and 29.51 % respectively.

Explanation:

For A:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of dimercaprol = 696 mg = 0.696 g (Conversion factor: 1 g = 1000 mg)

Molar mass of dimercaprol = 124.21 g/mol

Putting values in above equation, we get:

$\text{Moles of dimercaprol}=\frac{0.696g}{124.21g/mol}=0.0056mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 0.0056 moles of dimercaprol will contain $0.0056\times 6.022\times 10^{23}=3.4\times 10^{21}$ number of molecules.

As, 1 molecule of dimercaprol binds with 1 atom of Arsenic

So, $3.4\times 10^{21}$ number of dimercaprol molecules will bind with = $1\times 3.4\times 10^{21}=3.4\times 10^{21}$ number of arsenic atoms

Hence, the number of arsenic atoms are $3.4\times 10^{21}$

For B:

We know that:

Molar mass of dimercaprol = 124.21 g/mol

Molar mass of mercury = 200.59 g/mol

Molar mass of thallium = 204.38 g/mol

Molar mass of chromium = 51.99 g/mol

Also, 1 molecule of dimercaprol binds with 1 metal atom.

To calculate the percentage composition of metal in a complex, we use the equation:

$\%\text{ composition of metal}=\frac{\text{Mass of metal}}{\text{Mass of complex}}\times 100$ ......(1)

For mercury:

Mass of Hg-complex = (200.59 + 124.21) = 324.8 g

Mass of mercury = 200.59 g

Putting values in equation 1, we get:

$\%\text{ composition of mercury}=\frac{200.59g}{324.8g}\times 100=61.76\%$

For thallium:

Mass of Tl-complex = (204.38 + 124.21) = 328.59 g

Mass of thallium = 204.38 g

Putting values in equation 1, we get:

$\%\text{ composition of thallium}=\frac{204.38g}{328.59g}\times 100=62.2\%$

For chromium:

Mass of Cr-complex = (51.99 + 124.21) = 176.2 g

Mass of chromium = 51.99 g

Putting values in equation 1, we get:

$\%\text{ composition of chromium}=\frac{51.99g}{176.2g}\times 100=29.51\%$

Hence, the percent composition of mercury, thallium and chromium in their complexes are 61.76 %, 62.2 % and 29.51 % respectively.

8 0

3 years ago

Which lists the waves in order of frequency, from highest to lowest?

serg [7]

Radio waves.
microwaves.
infrared waves.
light.
ultraviolet waves (rays)
x-rays.
gamma rays.

6 0

3 years ago

Read 2 more answers