Answer:
v = 1.28 m/s
Explanation:
Given that,
Maximum compression of the spring, 
Spring constant, k = 800 N/m
Mass of the block, m = 0.2 kg
To find,
The velocity of the block when it first reaches a height of 0.1 m above the ground on the ramp.
Solution,
When the block is bounced back up the ramp, the total energy of the system remains conserved. Let v is the velocity of the block such that,
Initial energy = Final energy

Substituting all the values in above equation,

v = 1.28 m/s
Therefore the velocity of block when it first reaches a height of 0.1 m above the ground on the ramp is 1.28 m/s.
Answer:
The asteroid's acceleration at this point is
Explanation:
The equation that governs the trajectory of asteroid is given by :

The velocity of asteroid is given by :

At some point during the trip across the screen, the asteroid is at rest. It means, v = 0
So,
Acceleration,
Put t = 0.971 s

So, the asteroid's acceleration at this point is
and it is decelerating.
The answer is D, the amount of energy stays the same.
Answer:
The liquid formed from a melted solid has the same mass as the solid has.
Explanation:
As long as no water can escape, the mass of the ice before melting must equal the mass of the liquid water after.
<span>238,900 mi hope it helps :)</span>