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Bingel [31]
2 years ago
15

A 65kg swimmer pushes off the pool wall and accelerates at 6m/s2. The friction experienced by the swimmer is 100n. What is the m

agnitude of the force that the swimmer applies on the wall?.
Physics
1 answer:
charle [14.2K]2 years ago
5 0

Answer:

490 N

Explanation:

Fnet = ma

       = 65*6

       = 390 N

Net force is applied force (Fapp) and friction force (Ff) in the opposite direction.

Fnet= Fapp - Ff

390=x-100

x=490N

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An elevator is being pulled up from the ground floor to the third floor by a cable. The cable is exerting 4500 newtons of force
Delicious77 [7]

Answer:

The gravitational force on the elevator = 4500N

Explanation:

The given parameters are;

The force applied by the elevator, F  = 4500 N

The acceleration of the elevator = Not accelerating

From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;

F = W + Mass of elevator × Acceleration of elevator

∴ F = W + Mass of elevator × 0 = W

F = 4500 N = W

The net force on the elevator is F - W = 0

The gravitational force on the elevator = W = 4500N.

3 0
3 years ago
Explain what parallel medium boundaries do to the path of the wave after it travels through both boundaries. (air and water)
Brilliant_brown [7]

Answer:

The boundaries cause the waves to change direction an effect called <u>refraction.</u>

Explanation:

When a wave crosses a boundary between different materials, the speed of the wave and its wavelength changes.When passing from air to water the two properties (speed and wavelength) decreases, and the wave is observed to change direction as it crosses the boundary between the two material.The bending of the wave is called refraction.

7 0
3 years ago
How many molecules of Oxygen gas are there on the reactant side of this equation?
Sergeeva-Olga [200]

Answer:

4

Explanation:

It has 8 O atoms and 4 O2(g) molecules

8 0
2 years ago
A manager at a local bank analyzed the relationship between monthly salary and three independent variables: length of service (m
Readme [11.4K]

Answer:

a

Explanation:

8 0
3 years ago
A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t
nlexa [21]

To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

\Phi = BA Cos \theta

Here,

\theta = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

\epsilon= -N \frac{d\Phi }{dt}

\epsilon = -N \frac{(BAcos\theta)}{dt}

\epsilon = -NAcos\theta \frac{dB}{dt}

\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)

\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )

At time t = 5.71s,  Induced emf is,

\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)(  (3.05T/s)-(13.9T/s)(5.71s))

\epsilon = 10.9V

Therefore the magnitude of the induced emf is 10.9V

4 0
3 years ago
Read 2 more answers
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