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dlinn [17]
3 years ago
15

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

many carbon atoms are in 1.50 g of butane?
Chemistry
1 answer:
forsale [732]3 years ago
7 0
Doesnt the number of carbon atoms stay the same.
Though the weight of carbon in 1.5g is 1.24g.

This is because the RAM of C4 is 48.

The RFM of C4H10 is 58. Therefore, 48/58 is carbon in butane.

48/58 x 1.5 = 1.24g
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The decomposition of copper(II) nitrate on heating is endothermic reaction. 2Cu(NO3)2(s) → 2C10(s) + 4NO2(g) + O2(g) Calculate t
Basile [38]

Answer:

The enthalpy change for the given reaction is 424 kJ.

Explanation:

2Cu(NO_3)_2(s)\rightarrow 2CuO(s) + 4NO_2(g) + O_2(g),\Delta H_{rxn}=?

We have :

Enthalpy changes of formation of following s:

\Delta H_{f,Cu(NO_3)_2}=-302.9 kJ/mol

\Delta H_{f,CuO}=-157.3 kJ/mol

\Delta H_{f,NO_2}= 33.2 kJ/mol

\Delta H_{f,O_2}= 0 kJ/mol (standard state)

\Delta H_{rxn}=\sum [\Delta H_f(product)]-\sum [\Delta H_f(reactant)]

The equation for the enthalpy change of the given reaction is:

\Delta H_{rxn} =

=(2 mol\times \Delta H_{f,CuO}+4\times \Delta H_{f,NO_2}+1 mol\times \Delta H_{f,O_2})-(2mol\times \Delta H_{f,Cu(NO_3)_2})

\Delta H_{rxn}=

(2mol\times (-157.3 kJ/mol)+4\times 33.2 kJ/mol=1 mol\times 0 kJ/mol)-(2 mol\times (-302.9 kJ/mol)

\Delta H_{rxn}=424 kJ

The enthalpy change for the given reaction is 424 kJ.

6 0
4 years ago
What evidence supports conservation of matter?
Zinaida [17]

Answer:

i dont knoq

Explanation:

sorry that i couldnt help you

7 0
3 years ago
Suppose you are provided with a 30.86 g sample of potassium chlorate to perform this experiment. What is the mass of oxygen you
oee [108]

Answer:

The mass of oxygen is 12.10 g.

Explanation:

The decomposition reaction of potassium chlorate is the following:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

We need to find the number of moles of KClO₃:

\eta_{KClO_{3}} = \frac{m}{M}

Where:

m: is the mass = 30.86 g

M: is the molar mass = 122.55 g/mol

\eta_{KClO_{3}} = \frac{30.86 g}{122.55 g/mol} = 0.252 moles                                      

Now, we can find the number of moles of O₂ knowing that the ratio between KClO₃ and O₂ is 2:3

\eta_{O_{2}} = \frac{3}{2}*0.252 moles = 0.378 moles

Finally, the mass of O₂ is:

m = 0.378 moles*32 g/mol = 12.10 g

Therefore, the mass of oxygen is 12.10 g.

I hope it helps you!

6 0
3 years ago
1) A toy car with a mass of 2.35 kg is pushed with a force of 21.6 N. What is the acceleration of the car?
Nataly_w [17]

Answer:

The acceleration of the car is 9,19 m/s2

Explanation:

We use the formula: F=m x a---> a=F/m

a=21,6N/ 2,35kg       1N is 1kgxm/s2

a=21,6 kg x m/s2 x 2,35 kg

a=9,191489362  m/s2

6 0
4 years ago
Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water
Romashka [77]
The balanced reaction is 
Na2O + H2O --> 2NaOH

If 2.24 moles of sodium oxide react, that means 4.48 moles of NaOH is formed as it is a 1 to 2 stoichiometric relationship.

Now we multiply by the molar mass to get grams.

4.48 moles NaOH * (39.997 grams/1 mole) = 179.2 grams

Your answer is 179. grams.
6 0
3 years ago
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