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3 years ago

According to the theory of plate tectonics, which forces cause the movement of plates in the earth's crust?

Physics

2 answers:

Sauron [17]3 years ago

4 0

The correct answer is B.

Tresset [83]3 years ago

3 0

Your answer is C. Because Heat from the earth's interior that fuels convection currents which moves the crustal plates on the earth's surface.

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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.6 multiply 1010 m (inside t

Doss [256]

We will apply the concepts related to energy conservation to develop this problem. In this way we will consider the distances and the given speed to calculate the final speed on the path from the sun. Assuming that the values exposed when saying 'multiply' is scientific notation we have the following,

$d_1 = 4.6*10^{10}m$

$v_i = 9.3*10^4m/s \rightarrow \text{Initial velocity comet}$

$d_2 = 6*10^{12}m$

The difference of the initial and final energy will be equivalent to the work done in the system, therefore

$E_f = E_i +W$

$K_f +U_f = K_i +U_i + 0$

$\frac{1}{2} mv_f^2+\frac{-GMm}{d_2} = \frac{1}{2} mv_i^2+\frac{-GMm}{d_1}$

Here,

m = Mass

$v_f$ = Final velocity

G = Gravitational Universal Constant

M = Mass of the Sun

m = Mass of the comet

$v_i$ = Initial Velocity

Rearranging to find the final velocity,

$v_f = \sqrt{v_i^2+2GM(\frac{1}{d_2}-\frac{1}{d_1})}$

Replacing with our values we have finally,

$v_f = \sqrt{(9.3*10^4)+2(6.7*10^{-11})(1.98*10^{30})(\frac{1}{6*10^{12}}-\frac{1}{4.6*10^{10}})}$

$v_f = 75653.9m/s$

Therefore the speed is 75653m/s

8 0

4 years ago

19. A mass of gas has a volume of 4 m3, a temperature of 290 K, and an absolute pressure of 475 kPa. When the gas is allowed to

Aleks [24]

Recall this gas law:

$\frac{P₁V₁}{T₁}$ = $\frac{P₂V}{T₂}$

P₁ and P₂ are the initial and final pressures.

V₁ and V₂ are the initial and final volumes.

T₁ and T₂ are the initial and final temperatures.

Given values:

P₁ = 475kPa

V₁ = 4m³, V₂ = 6.5m³

T₁ = 290K, T₂ = 277K

Substitute the terms in the equation with the given values and solve for Pf:

$\frac{475*4}{290} = \frac{P₂*6.5}{277}$

8 0

3 years ago

Magnetic fields are produced by: atoms currents voltages charges

baherus [9]

The answer is currents

3 0

4 years ago

A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 mT magnetic field is perpendic

Lerok [7]

Answer:

<h2>The potential difference is 60mV</h2>

Explanation:

This problem bothers on application of the expression for motion emf which is expressed as

$E= Blv$

where B= magnetic field in Tesla

l= length of the conductor

v= speed of conductor

Given data

l= 2 meters

v= 6 m/s

B= 5 Tesla

Applying the formula we have

$E=5*2*6= 60mV$

7 0

3 years ago

A transverse, wave travelling on a chord is represented by D=0.22sin (5.6x+34t) where D and x are inmeters and t is in seconds.

ArbitrLikvidat [17]

Answer:

a) λ = 1.12 m

b) f = 5.41 Hz

c) v = 154.54 m/s

d) A = 0.22m

$v_D_{max}=7.48\frac{m}{s}\\\\v_D_{min}=-7.48\frac{m}{s}\\\\$

Explanation:

You have the following equation for a wave traveling on a cord:

$D=0.22sin(5.6x+34t)$ (1)

The general expression for a wave is given by:

$D=Asin(kx-\omega t)$ (2)

By comparing the equation (1) and (2) you have:

A: amplitude of the wave = 0.22m

k: wave number = 5.6 m^-1

w: angular velocity = 34 rad/s

a) The wavelength is given by substitution in the following expression:

$\lambda=\frac{2\pi}{k}=\frac{2\pi}{5.6m^{-1}}=1.12m$

b) The frequency is:

$f=\frac{\omega}{2\pi}=\frac{34s^{-1}}{2\pi}=5.41Hz$

c) The velocity of the wave is:

$v=\frac{\omega}{k}=\frac{34s^{-1}}{0.22m^{-1}}=154.54\frac{m}{s}$

d) The amplitude is 0.22m

e) To calculate the maximum and minimum speed of the particles you obtain the derivative of the equation of the wave, in time:

$v_D=\frac{dD}{dt}=(0.22)(34)cos(5.6x+34t)\\\\v_D=7.48cos(5.6x+34t)$

cos function has a minimum value -1 and maximum +1. Then, you obtain for maximum and minimum velocity:

$v_D_{max}=7.48\frac{m}{s}\\\\v_D_{min}=-7.48\frac{m}{s}\\\\$

6 0

3 years ago