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2 years ago

7

What name should be used for the ionic compound LiI?

2 answers:

Gelneren [198K]2 years ago

8 0

<u>Answer: </u>The given compound is named as lithium iodide.

<u>Explanation:</u>

$LiI$ is an ionic compound because lithium is a metal and Iodine element is a non-metal.

We know that, a bond which is formed between a metal and a non-metal is always ionic in nature.

Ionic bond is formed when there is a complete transfer of electron from an electropositive element (a metal) to an electronegative element (non-metal).

The nomenclature of ionic compounds is given by:

Positive ion is always written first.
The negative ion is written next with a suffix added at the end of the negative ion. The suffix used is '-ide'.

Hence, the name given to $LiI$ will be lithium iodide.

timurjin [86]2 years ago

5 0

What name should be used for the ionic compound LiI?

The name that should be used for the ionic compound LiI is Lithium iodide. When naming ionic compounds, you have to take into consideration pairing of two components.

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The crystal structure of an ionic compound depends on the

Murljashka [212]

Answer:

The ion's sizes and their radius ratio.

Explanation:

Ionic compounds take the form of three dimentional arrays by alternating anions and cations in order to minimize the potential energy of the system by maximizing the attractive force between opposite charges.

<em>The resultant geometric structures are known as crystal lattices and their arrangements depend on the ion's sizes and, since they are bound though electrostatic attraction, their radius ratio.</em>

I hope you find this information useful and interesting! Good luck!

4 0

3 years ago

iron combines with oxygen to form rust. given the chemical reaction, how many grams of rust would be produced if 3 grams of reac

tia_tia [17]

Answer:

I believe its 1 gram

Explanation:

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3 years ago

What kind of glacier has pieces that breaks off as icebergs

forsale [732]

There is no specific name for a glacier that break off as an iceberg. However, the part of the glacier in which this happens is called the "zone of wastage". Chunks break off in a process called "calving".

5 0

3 years ago

Write a double replacement precipitation reaction A precipitate forms when aqueous solutions of nickel(II) chloride and silver(I

harkovskaia [24]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

Double displacement reaction is defined as the reaction in which exchange of ions takes place.

$AB+CD\rightarrow CB+AD$

Precipitation reaction is defined as the reaction in which an insoluble salt is formed when two solutions are mixed containing soluble substances. The insoluble salt settles down at the bottom of the reaction mixture.

When nickel (II) chloride reacts with silver (I) nitrate, it leads to the formation of white precipitate of silver chloride and an aqueous solution of nickel (II) nitrate.

The balanced chemical equation for the above reaction follows:

$NiCl_2(aq.)+2AgNO_3(aq.)\rightarrow 2AgCl(s)+Ni(NO_3)_2(aq.)$

By Stoichiometry of the reaction:

1 mole of aqueous solution of nickel (II) chloride reacts with 2 moles of aqueous solution of silver (I) nitrate to produce 2 moles of solid silver chloride and 1 moles of aqueous solution of nickel (II) nitrate

Hence, the balanced chemical equation is written above.

3 0

3 years ago

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago