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morpeh [17]
3 years ago
11

The perimeter of a trapezoid is 39a-7. Three sides have the following length:9a,5a+1, and 17a-6. What is the length of the forth

side?
Mathematics
1 answer:
aalyn [17]3 years ago
5 0

Then, it would be:

39a-7 = 9a+5a+1+17a-6+x

39a-7 = 31a-5+x

x= 39a-31a-7+5

x = 8a-2

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PolarNik [594]

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4 0
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3 lines are shown. A line with points C, A, F intersects a line with points E, A, B at point A. A line extends from point A to p
Verizon [17]

Answer:

m < EAD = 29 degrees

m < CAB = 119 degrees

Given :

The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees

Solution:

1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)

2. m<BAC + m<EAC = 180 degrees (sum of linear pair)

3. m<CAB = 180 degrees - m<EAC

4. Equation 1: m<CAB = m<EAF = 119 degrees

5. m<EAF = m<EAD + m< DAF

6. m<EAD = m<EAF - m<DAF

7. m<EAD = 119 degrees-90 degrees = 29 degrees

Hope this helps!!! :)

Attached photo work is created by another brainly user named tallinn.

Click on this link to find his work and possibly more information of the answer. Thanks!

5 0
3 years ago
Can someone help me!!!
Eva8 [605]
\text {Distance} =  \sqrt{(7-0)^2 + (-6+3)^2} =  \sqrt{7^2+(-3)^2} =  \sqrt{58} = 7.6 \text{ units}

Answer: 7.6 units
7 0
4 years ago
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