<u>Answer:</u> The average speed of the plane in northeast direction is 816 km/hr and that in upward direction is 6.4 km/hr
<u>Explanation:</u>
Average speed is defined as the ratio of total distance traveled to the total time taken.
To calculate the average speed of the runner, we use the equation:
.......(1)
Total distance traveled = 204 km
Total time taken = 15.0 mins = 0.25 hr (Conversion factor: 1 hr = 60 mins)
Putting values in equation 1, we get:
Total distance traveled = 1.6 km
Total time taken = 15.0 mins = 0.25 hr
Putting values in equation 1, we get:
Hence, the average speed of the plane in northeast direction is 816 km/hr and that in upward direction is 6.4 km/hr
Answer:
4086 J
Explanation:
The potential energy is transformed to kinetic energy less the frictional energy. Potential energy= mgh where m represent mass, g is acceleration due to gravity and h is the height of cliff
Since we have force of air resistance, work done due to air resistance will be product of force and distance
Substituting 10 Kg for m, 9.81 for g and 60 m for F then the kinetic energy at the bottom will be
KE= 10*9.81*60- (30*60)=4086 J
Answer:
C. Pressure gradient equals gas flow over resistance.
Explanation:
As we know that pressure gradient is the driving force for the gas to flow from one point to other point
And we know that the flow rate is directly proportional to the driving force and it inversely depends on the resistance to flow
so we can say
Flow Rate =
Flow Rate =
so we can say that correct statements are as below
A. Gas flow equals pressure gradient over resistance.
B. Resistance equals pressure gradient over gas flow.
D. The amount of gas flowing in and out of the alveoli is directly proportional to the difference in pressure or pressure gradient between the external atmosphere and the alveoli.
Forward thrust has positive values and reverse thrust has negative values.
Thrust is a sudden push or pull in a certain direction.
a)
Flight speed u = 150 km/h
1 km/h = km/s
therefore, 150 km/h = 41.67 km / s
The thrust force represents the horizontal or x-component of momentum equation:
T = 50 * (150 - 41.67)
T = 5416.67 N
Therefore, the value of forward thrust is 5416.67 N.
b)
Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,
thus thrust equation is:
T = 50 * (0 - 41.67)
T = -2083.5 N
Therefore, the thrust force T is -2083.5 N in the reverse direction.
c)
Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero because
T = 0
Therefore, there is no difference in two velocities in x direction.
The given question is incomplete, the complete question is,
"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.
a. What is the forward thrust of this engine?
b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?
c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"
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