Answer:
197 grams
Explanation:
Without taking into account the number of sig figs you have for your values, you can say that the answer will once again be
197 g of aluminium bromide.
(I hope this is right)
153.888 grams are in 4.8 moles of sulfur
The molarity of the hydrochloric acid, HCl solution given the data is 0.079 M
<h3>Balanced equation </h3>
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
- The mole ratio of the acid, HCl (nA) = 1
- The mole ratio of the base, NaOH (nB) = 1
<h3>How to determine the molarity of HCl </h3>
- Molarity of base, NaOH (Mb) = 0.137 M
- Volume of base, NaOH (Vb) = 16.1 mL
- Volume of acid, HCl (Va) = 27.9 mL
- Molarity of acid, HCl (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 27.9) / (0.137 × 16.1) = 1
(Ma × 27.9) / 2.2057 = 1
Cross multiply
Ma × 27.9 = 2.2057
Divide both side by 27.9
Ma = 2.2057 / 27.9
Ma = 0.079 M
Thus, the molarity of the HCl solution is 0.079 M
Learn more about titration:
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Answer:
When these atoms gain electrons, they acquire a negative charge because they now possess more electrons than protons. Negatively charged ions are called anions. Most nonmetals become anions when they make ionic compounds. A neutral chlorine atom has seven electrons in its outermost shell.
Explanation:
Hope this helps!
