Answer:
5.01%
Explanation:
Density of vinegar = mass/volume
Mass of 10.00 mL = density x volume
= 1.006 x 10 = 10.06 g
From the equation of reaction:
1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.
mole of NaOH = molarity x volume
= 0.5062 x 0.01658
= 0.008392796 mole
0.008392796 mole of NaOH will therefore require 0.008392796 mole of CH3COOH.
mass of CH3COOH = mole x molar mass
= 0.008392796 x 60.052
= 0.504 g
Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%
= 5.01%
The percent by mass of acetic acid in the vinegar is 5.01%
The answer for this question is B) Ionization and Dissociation because Dissociation happens, charged particles form (ions), and since the ions didn't exist before the substance was dissolved, this process is called IONIZATION. It is the process that involves the formation of ions, a conversion of a substance into ions.
Because Boron likes to lose 3 electrons when it undergoes ionization, we draw a boron ion like a helium atom, with just 2 electrons in the first shell, and 0 in the second
The correct answer is (1) one mole of NO2.
The gram formula mass is also known as the molar mass and is defined by the mass over one mole of a substance.
Hope this helps~
B. The limiting reactant determines the max amount of product that can be formed
