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Alexandra [31]
4 years ago
11

How many grams are in 4.8 moles of Sulfur?

Chemistry
1 answer:
Ainat [17]4 years ago
5 0
153.888 grams are in 4.8 moles of sulfur
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Calculate the mass of hydrogen in 57.010 grams of ammonium hydrogen phosphate. Use dimensional analysis.
adell [148]

Answer:

4.59 grams of hydrogen

Explanation:

57.010 g of ammonium phosphate * 1 mol / 149 g of ammonium phosphate * 12.0 g H * / 1 mol = 4.591409396.

But with sig figs, it rounds to 4.59.

So the final answer is 4.59 grams of hydrogen.

6 0
3 years ago
Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:
dybincka [34]

Answer:

0.29

Explanation:

Step 1: Write the balanced equation at equilibrium

3 NO₂(g) + H₂O(l) ⇄ 2 HNO₃(aq) +  NO(g)

Step 2: Calculate the molar concentration of the substances

We will not calculate the molarity of H₂O because pure liquids are not included in the equilibrium constant. We will use the following expression.

Molarity = mass of solute / molar mass of solute × liters of solution

Since the volume of the vessel is missing, we will assume it is 1 L to see the procedure.

[NO₂] = 22.5 / 46.01 g/mol × 1 L = 0.489 M

[HNO₃] = 15.5 g / 63.01 g/mol × 1 L = 0.246 M

[NO] = 16.6 g / 30.01 g/mol × 1 L = 0.553 M

Step 3: Calculate the value of the equilibrium constant Kc for this reaction

Kc = [HNO₃]² × [NO] / [NO₂]³

Kc = 0.246² × 0.553 / 0.489³

Kc = 0.29

7 0
3 years ago
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO 3 ( s ) . The equation for the
Pavlova-9 [17]

Answer:

Mass of O_2 produced = 32 g

Explanation:

Calculation of the moles of KClO_3 as:-

Mass = 82.4 g

Molar mass of KClO_3 = 122.55 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{82.4\ g}{122.55\ g/mol}

Moles= 0.67237\ mol

From the reaction shown below:-

2KClO_3\rightarrow 2KCl+3O_2

2 moles of potassium chlorate on reaction forms 3 moles of oxygen gas

So,

0.67237 moles of potassium chlorate on reaction forms \frac{3}{2}\times  0.67237 moles of oxygen gas

Moles of oxygen gas = 1 mole

Molar mass of oxygen gas  = 32 g/mol

<u>Mass of O_2 produced = 32 g</u>

6 0
4 years ago
How is precipitation useful in our daily lives?
Alex73 [517]

Answer:

The precipitation reaction is the double displacement reaction in which  two ionic bonds combine forming up insoluble salts.

Precipitation reaction can be used in our daily life in events such as in waste water treatment. When a contaminant forms an insoluble solid, then we can use this reaction to precipitate out the contaminated ions.

The rings which form in the bathtubs are also an example of the precipitation reactions.

3 0
4 years ago
PLEASE HELP!! Phytoplankton are one of the most important parts of the food web in the Hudson river. what evidence supports the
Sedaia [141]

Answer:

Your answer is b

Explanation:

the answer is b because if there is no phytoplankton then there will be no fish and if you take out one part of the food chain then the whole chain comes apart. So meaning if there is no phytoplankton, then there is no fish, if there isn't any fish, then the other animals that come to eat at the river will eventually starve to death or move somewhere else to get more food.

7 0
3 years ago
Read 2 more answers
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