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Lemur [1.5K]
3 years ago
15

A garden hose with an internal diameter of 2.9 cm is connected to a (stationary) lawn sprinkler that consists merely of a contai

ner with 24 holes, each 0.36 cm in diameter. If the water in the hose has a speed of 0.98 m/s, at what speed does it leave the sprinkler holes?
Physics
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

Water leaves the holes with a speed of 2.65 m/sec    

Explanation:

It is given internal diameter of garden hose = 2.9 cm

So internal radius r_1=\frac{2.9}{2}=1.45cm

Number of holes n = 24

Diameter of holes d = 0.36 cm

So radius of holes r_2=\frac{0.36}{2}=0.18cm

Velocity of water in hose  v_1=0.98m/sec

According to continuity equation

A_1v_1=nA_2v_2

\pi r_1^2\times 0.98=24\times \pi r_2^2\times \times v_2

1.45^2\times 0.98=24\times  0.18^2\times \times v_2

v_2=2.65m/sec

Therefore water leaves the holes with a speed of 2.65 m/sec

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