Question

What is the final chemical equation from the following intermediate chemical equations?

Answer 1

the answer to that question is a

Answer 2

Answer : The correct option is, (1) $P_4O_6(s)+2O_2(g)\rightarrow P_4O_{10}(s)$

Explanation :

The two intermediate chemical equations are :

$P_4O_6(s)\rightarrow P_4(s)+3O_2(g)$     ..............(1)

$P_4(s)+5O_2(g)\rightarrow P_4O_{10}(s)$    .............(2)

Now adding equation (1) and equation (2), we get

$P_4O_6(s)+P_4(s)+5O_2(g)\rightarrow P_4(s)+3O_2(g)+P_4O_{10}(s)$

Now we will cancel the $P_4(s)$ from both the sides of the equation, we get

$P_4O_6(s)+5O_2(g)\rightarrow 3O_2(g)+P_4O_{10}(s)$

Now we will subtracting $3O_2(g)$ from the $5O_2(g)$, we get

$P_4O_6(s)+2O_2(g)\rightarrow P_4O_{10}(s)$

This is the final chemical equation.