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Lorico [155]
3 years ago
8

Calculate the solubility at of AgCl in pure water and in a ).0010 M solution. You'll find data in the ALEKS Data tab. Round both

of your answers to significant digits.
Chemistry
1 answer:
Julli [10]3 years ago
3 0

Answer:

1.34x10⁻⁵ mol / L is the solubility of AgCl

Explanation:

Ksp of AgCl is defined as:

AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)

If 0.010M of AgCl is added, some Ag⁺ and Cl⁻ will be produced until:

Ksp = [Ag⁺] [Cl⁻]

Ksp for AgCl = 1.8x10⁻¹⁰ (Taken from ALEKS Data tab):

Some Ag⁺ and Cl⁻ are produced, you can take this "some" as X:

[Ag⁺] = X

[Cl⁻] = X

<em>Where X is the amount of AgCl that dissolvesin water. X = solubility:</em>

Ksp = 1.8x10⁻¹⁰ = [Ag⁺] [Cl⁻]

1.8x10⁻¹⁰ = [X] [X]

1.8x10⁻¹⁰ = X²

X =

<h3>1.34x10⁻⁵ mol / L is the solubility of AgCl</h3>
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5 0
3 years ago
How many grams are in 1.70 moles of Ca(NO3)2?
Andru [333]

The number of grams in 1.70 moles of Ca(NO₃)₂ is 384.2 grams

<h3>How to determine the mass of Ca(NO₃)₂</h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

With the above formula, we can determine the mass of Ca(NO₃)₂ as illustrated below:

  • Mole of Ca(NO₃)₂ = 1.70 moles
  • Molar mass of Ca(NO₃)₂ = 40 + 3[14 + (16 × 3)] = 40 + 3[14 + 48] = 40 + 3(62) = 40 + 186 = 226 g/mol
  • Mass of Ca(NO₃)₂ = ?

Mole = mass / molar mass

1.70 = Mass of Ca(NO₃)₂ / 226

Cross multiply

Mass of Ca(NO₃)₂ = 1.70 × 226

Mass of Ca(NO₃)₂ = 384.2 grams

Thus, the mass of 1.70 moles of Ca(NO₃)₂ is 384.2 grams

Learn more about mole:

brainly.com/question/13314627

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3 years ago
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Answer:

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