Answer:
Please see attachment for the computation.
The answer is γ(θ) = 2αVα((1+cosθ)/sinθ)
Explanation:
Please look at the image for the explanation of the answer
thickness1=1.4m
thickness2=2.2m
convection coefficient=0.33W/m^2K
you must use this equation to calculate the thickness:
L=K(T2-T1)/Q
L=thickness
T=temperature
Q=heat
L1=0.04*(0--350)/10=1.4m
L2=0.1(220-0)/10=2.2m
Then use this equation to calculate the convective coefficient
H=Q/(T2-T1)
H=10/(250-220)=0.33W/m^2K
Option A
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