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jek_recluse [69]
3 years ago
13

Cual es la definición de la distribución de las instalaciones?

Engineering
2 answers:
Nat2105 [25]3 years ago
7 0

Answer:

Nao ablo espanhol

Explanation:

jeka57 [31]3 years ago
6 0
La distribución de las instalaciones consiste en determinar dónde se colocarán los departamentos, los grupos de trabajo de los departamentos, las estaciones de trabajo y los puntos donde se guardan los materiales de trabajo dentro de una instalación productiva. El objetivo es ordenar estos elementos de manera que se garantice el flujo continuo del trabajo en una fábrica o un patrón de tránsito dado en una organización de servicios.
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A three-point bending test is performed on a glass specimen having a rectangular cross section of height d = 5.4 mm (0.21 in.) a
Fudgin [204]

Answer:

5.21e-2mm

Explanation:

Please see attachment

8 0
3 years ago
A lagoon is designed to accommodate an input flow of 0.10 m^3/s of nonconservative pollutant with concentration 30 mg/L and deca
dexar [7]

Answer:

Volume of the lagoon required for the decay process must be larger than 86580 m³ = 8.658 × 10⁷ L

Explanation:

The lagoon can be modelled as a Mixed flow reactor.

From the value of the decay constant (0.2/day), one can deduce that the decay reaction of the pollutant is a first order reaction.

The performance equation of a Mixed flow reactor is given from the material and component balance thus:

(V/F₀) = (C₀ - C)/((C₀)(-r)) (From the Chemical Reaction Engineering textbook, authored by Prof. Octave Levenspiel)

V = volume of the reactor (The lagoon) = ?

C₀ = Initial concentration of the reactant (the pollutant concentration) = 30 mg/L = 0.03 mg/m³

F₀ = Initial flow rate of reactant in mg/s = 0.10 m³/s × C₀ = 0.1 m³/s × 0.03 mg/m³ = 0.003 mg/s

C = concentration of reactant at any time; effluent concentration < 10mg/L, this means the maximum concentration of pollutant allowed in the effluent is 10 mg/L

For the sake of easy calculation, C = the maximum value = 10 mg/L = 0.01 mg/m³

(-r) = kC (Since we know this decay process is a first order reaction)

This makes the performance equation to be:

(kVC₀/F₀) = (C₀ - C)/C

V = F₀(C₀ - C)/(kC₀C)

k = 0.2/day = 0.2/(24 × 3600s) = 2.31 × 10⁻⁶/s

V = 0.003(0.03 - 0.01)/(2.31 × 10⁻⁶ × 0.03 × 0.01)

V = 86580 m³

Since this calculation is made for the maximum concentration of 10mg/L of pollutant in the effluent, the volume obtained is the minimum volume of reactor (lagoon) to ensure a maximum volume of 10 mg/L of pollutant is contained in the effluent.

The lower the concentration required for the pollutant in the effluent, the larger the volume of reactor (lagoon) required for this decay reaction. (Provided all the other parameters stay the same)

Hope this helps!

5 0
3 years ago
A 5­stage single pipeline computer uses the pipeline mentioned in the lecture (not the book). It resolves the direction and targ
brilliants [131]
I have no idea sorry
7 0
3 years ago
The federal highway administration reports nearly
levacccp [35]

Explanation:

The federal highway administration reports nearly 800 work zone fatalities per year.

8 0
3 years ago
What measures can be taken to mitigate or prevent the formation of stress corrosion cracks?
sasho [114]

Answer:

a) Selection and control of material

b) Control of stress

c) Control of the environment

Explanation:

The measures that can be taken to control and prevent the formation of strss corrosion cracks are:

a) Selection and control of material

It deals with the selection of the best quality material that can resist the stress corrosion cracks to a high extent.

b) Control of stress

It is to control or reduce the intensity of the major stress that causes the stress corrosion cracks.

c) Control of the environment

It includes the prevention of the material from the corrosive environment by removing the component from the region or controlling the environment condition around the object.

7 0
3 years ago
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