All categories

3 years ago

How does the energy of core electrons compare with the energy of valence electrons?

Chemistry

2 answers:

klemol [59]3 years ago

8 0

Answer:

1. The energy difference between core electrons and valence electrons is different since it would require high amount of energy to lose electron from the core shell compared to the valence shell.

2. The electrostatic attraction between the varies. The closer the electron is to the core (nucleus) the more it experiences a strong nuclear force which in turn weakens the valence electron. During the process, the core electrons shield the valence electrons from exposure to nuclear force and hence easily lost during chemical reactions.

3. Core electrons only participate during nuclear reactions while valence electrons are responsible for chemical reactions through exchange of electrons between atoms.

Simora [160]3 years ago

4 0

The energy of the valence electrons is greater than the energy of the core electrons

You might be interested in

which of the following lewis diagrams best represents the bonding in the N2O molecule, considering formal charges? justify your

avanturin [10]

The best diagram to represent N2O is the second diagram.

The Lewis diagram is used to represent the way two or more atoms bond. This is possible by using lines to represent bonds and dots to represent electrons.

In the case of the molecule N2O bonding occurs in the following way:

A triple bond is formed between the nitrogen atoms, which means, in the Lewis diagram the nitrogen atoms are connected with three lines.
The oxygen atom connects to one of the nitrogen atoms.
The nitrogen atom that is not connected to the oxygen will have 2 electrons represented by dots because the number of valence electrons is 5, but three were used in the triple bond.
The oxygen atom will have 6 electrons represented by dots, which are equal to the number of valence electrons.

Learn more about Lewis diagram in: brainly.com/question/9436176

8 0

3 years ago

This response to stimuli is very important in protecting the eyes because although they need light to see, too much light can ca

Dimas [21]

A. The nervous system works without the aid of other systems in order to provide a sufficiently rapid response.

7 0

3 years ago

Read 2 more answers

A volume of 30.0 mL of a 0.140 M HNO3 solution is titrated with 0.570 M KOH. Calculate the volume of KOH required to reach the e

igomit [66]

Answer:

7.37 mL of KOH

Explanation:

So here we have the following chemical formula ( already balanced ), as HNO3 reacts with KOH to form the products KNO3 and H2O. As you can tell, this is a double replacement reaction,

HNO3 + KOH → KNO3 + H2O

Step 1 : The moles of HNO3 here can be calculated through the given molar mass ( 0.140 M HNO3 ) and the mL of this nitric acid. Of course the molar mass is given by mol / L, so we would have to convert mL to L.

Mol of NHO3 = 0.140 M $*$ 30 / 1000 L = 0.140 M $*$ 0.03 L = .0042 mol

Step 2 : We can now convert the moles of HNO3 to moles of KOH through dimensional analysis,

0.0042 mol HNO2 $*$ ( 1 mol KOH / 1 mol HNO2 ) = 0.0042 mol KOH

From the formula we can see that there is 1 mole of KOH present per 1 moles of HNO2, in a 1 : 1 ratio. As expected the number of moles of each should be the same,

Step 3 : Now we can calculate the volume of KOH knowing it's moles, and molar mass ( 0.570 M ).

Volume of KOH = 0.0042 mol $*$ ( 1 L / 0.570 mol ) $*$ ( 1000 mL / 1 L ) = 7.37 mL of KOH

5 0

4 years ago

A warm air is rising as cooler air es in to take its place. what is the name for that?

klasskru [66]

Answer:

convection

hope this helps

have a good day :)

Explanation:

6 0

3 years ago

How many moles of O2 are needed to burn 2.56 moles of CH3OH?

lukranit [14]

Answer:

$n_{O_2}=3.84molO_2$

Explanation:

Hello!

In this case, since the combustion reaction of methanol is:

$CH_3OH+\frac{3}{2} O_2\rightarrow CO_2+2H_2O$

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

$n_{O_2}=2.56molCH_3OH*\frac{\frac{3}{2}molO_2}{1molCH_3OH} \\\\n_{O_2}=3.84molO_2$

Best regards!

6 0

3 years ago