Lifting a mass to a height, you give it gravitational potential energy of
(mass) x (gravity) x (height) joules.
To give it that much energy, that's how much work you do on it.
If 2,000 kg gets lifted to 1.25 meters off the ground, its potential energy is
(2,000) x (9.8) x (1.25) = 24,500 joules.
If you do it in 1 hour (3,600 seconds), then the average power is
(24,500 joules) / (3,600 seconds) = 6.8 watts.
None of these figures depends on whether the load gets lifted all at once,
or one shovel at a time, or one flake at a time.
But this certainly is NOT all the work you do. When you get a shovelful
of snow 1.25 meters off the ground, you don't drop it and walk away, and
it doesn't just float there. You typically toss it, away from where it was laying
and over onto a pile in a place where you don't care if there's a pile of snow
there. In order to toss it, you give it some kinetic energy, so that it'll continue
to sail over to the pile when it leaves the shovel. All of that kinetic energy
must also come from work that you do ... nobody else is going to take it
from you and toss it onto the pile.
The vertical height of the given plane is 4.9 m.
The given parameters:
- <em>speed of the object at the bottom of the ramp, v = 9.8 m/s</em>
The vertical height of the plane is calculated by applying principle of conservation of mechanical energy as follows;
Thus, the vertical height of the given plane is 4.9 m.
Learn more about conservation of mechanical energy here: brainly.com/question/332163
Chemical because rust is also called iron oxide (Fe2O3) and it occurs when oxygen bonds with iron atoms
Superman was a man who fell of the tree because he was up high at 98m and the. Tried to rescured Annie
Answer:
correct answer is (c) 15 J
Explanation:
given data
mass m1 = 2 kg
velocity V1 = 5 m/s
mass other = 3 kg
so mass m2 = 2+ 3 kg = 5 kg
solution
we will apply here conservation of momentum:
m1V1 = m2V2 ..........................1
put here value and we get velocity v2
(2.0) × (5.0) = (2.0 + 3.0) × V
solve it we get
10 = 5 × V
2
V2 = 2.0 m/s
so here kinetic energy will be
KE = ½ × m × v²
so
∆KE = ½ × m1 × (v1)² - ½ × m2 × (v2)
²
∆KE = 0.5 × 2 × 25 - 0.5 × 5 × 4
∆KE = 25 - 10
∆KE = 15 J
