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3 years ago

A car of mass 2000 kg is thrusted forward with an engine force of 2000 N and a total frictional

Physics

1 answer:

PolarNik [594]3 years ago

6 0

Answer:

40.3 m/s

Explanation:

We'll begin by calculating the resultant force.

Resultant force = 2000 – 1000 = 1000N

Next we shall determine the acceleration of the car. This is illustrated below:

Mass of the car = 2000kg

Resultant Force = 1000N

Acceleration =.?

Resultant Force = Mass x Acceleration

1000 = 2000 x Acceleration

Divide both side by 2000

Acceleration = 1000/2000

Acceleration = 0.5m/s²

Finally, we shall determine velocity of the car when it has moved 1000m.

Initial velocity (u) = 25m/s

Acceleration (a) = 0.5m/s²

Distance (s) = 1000m

Final velocity (v) =..?

Applying the formula v² = u² + 2as we can obtain the velocity of the car at 1000m as follow:

v² = u² + 2as

v² = 25² + 2(0.5 x 1000)

v² = 625 + 2(500)

v² = 625 + 1000

v² = 1625

Take the square root of both side

v = √1625

v = 40.3 m/s

Therefore, the speed of the car when it has moved 1000m is 40.3 m/s

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the momentum of a spring coil when the external compressing force is removed b the difference between the final momentum and the

Fed [463]

Answer:

the correct one is b

the difference between the final moment and the initial moment

Explanation:

The momentum is related to the moment

I = ΔP

∫ F dt = p_f - p₀

where p_f and p₀ are the final and initial moments, respectively

When checking the different answers, the correct one is b

the difference between the final moment and the initial moment

7 0

3 years ago

A car drives 24 meters to the left in three seconds what is the velocity of the car?

sineoko [7]

Answer:

8 m/s to the left.

Explanation:

Applying,

V = d/t...................... Equation 1

Where V = Velocity of the car, d = distance, t = time

From the question,

Given: d = 24 meters, t = 3 seconds

Substitute these values into equation 1

V = 24/3

V = 8 m/s to the left.

Hence the velocity of the car is 8 m/s to the left.

5 0

3 years ago

Two gliders on an air track collide in a perfectly elastic collision. Glider A has a mass of 1.1 kg and is initially travelling

Eva8 [605]

m1= mass 1 = 1.1 kg

Vi1 = initial velocity 1 = 2.7 m/s

m2= 2.4 kg

V2i = -1.9 m/s

We assume east as positive and west as negative.

Apply the formulas:

Vf1 = ?

$vf1=(\frac{m1-m2}{m1+m2})Vi1+(\frac{2m2}{m1+m2})Vi2$

Replacing:

$Vf1=\frac{(1.1-2.4)}{(1.1+2.4)}2.7+\frac{(2\times2.4)}{(1.1+2.4)}-1.9$ $Vf1=(\frac{-1.3}{3.5})2.7+(\frac{4.8}{3.5})-1.9$ $Vf1=-1-2.6=-3.6\text{ m/s}$

Answer: 3.6 m/s west

6 0

1 year ago

The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere

spin [16.1K]

Answer:

P = 0.0644 atm

Explanation:

Given that,

The pressure of a sample of gas is measured as 49 torr.

We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

1 atm = 760 torr

1 torr = (1/760) atm

49 torr = (49/760) atm

= 0.0644 atm

Hence, the presssure of the sample of gas is equal to 0.0644 atm.

5 0

2 years ago

As Clinton walks he pushes his shoe against the track.

Valentin [98]

Answer:A:The track pushes back on Clinton's shoe with the same force.

Explanation:According to Newton's third law of motion, for every action force there is an equal and opposite reaction force. In this case, the action force is Clinton's shoe pushing on the track. As this happens, there is an equal and opposite reaction force in which the track pushes back on Clinton's shoe with the same force.

4 0

3 years ago