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MaRussiya [10]
3 years ago
12

A car of mass 2000 kg is thrusted forward with an engine force of 2000 N and a total frictional

Physics
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

40.3 m/s

Explanation:

We'll begin by calculating the resultant force.

Resultant force = 2000 – 1000 = 1000N

Next we shall determine the acceleration of the car. This is illustrated below:

Mass of the car = 2000kg

Resultant Force = 1000N

Acceleration =.?

Resultant Force = Mass x Acceleration

1000 = 2000 x Acceleration

Divide both side by 2000

Acceleration = 1000/2000

Acceleration = 0.5m/s²

Finally, we shall determine velocity of the car when it has moved 1000m.

Initial velocity (u) = 25m/s

Acceleration (a) = 0.5m/s²

Distance (s) = 1000m

Final velocity (v) =..?

Applying the formula v² = u² + 2as we can obtain the velocity of the car at 1000m as follow:

v² = u² + 2as

v² = 25² + 2(0.5 x 1000)

v² = 625 + 2(500)

v² = 625 + 1000

v² = 1625

Take the square root of both side

v = √1625

v = 40.3 m/s

Therefore, the speed of the car when it has moved 1000m is 40.3 m/s

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Answer:

if the weight theoretically decreases at this height, but in a fraction of 10⁻⁵, which is not appreciable in any scale, therefore, the reading of the scale in the two places is the same.

Explanation:

The weight of a person in the force with which the Earth attracts the person, therefore can be calculated using the law of universal attraction

          F = G m M / r²

Where m is the mass of the person, M the masses of the earth

Let's call the person's weight at ground level as Wo and suppose the distance to the center of the Earth is Re

            W₀ = G m M / Re²

In the calculation of the weight of the person on the 100th floor the only thing that changes is the distance

          r = Re + 100 r₀

Where r₀ is the distance between the floors, which is approximately 2.5 m, so the distance is

         r = Re + 250

We substitute

     W = G m M / r²

      W = G m M / (Re + 250)²

The value of Re is 6.37 10⁶ m, so we can take it out as a factor and perform a serial expansion of the remaining fraction

      W = G m M / Re² (1+ 250 / Re)²

      (1 + 250 / Re)⁻² = 1 + (-2) 250 / Re + (-2 (-2-1)) / 2 (250 / Re)² +….

The value of the expression is

      (1 + 250 / Re)⁻² = 1 -2 250 / 6.37 10⁶ -30 (250 / 6.37)² 10⁻¹² + ...

We can see that the quadratic term is very small, which is why we despise it, we substitute in the weight equation

      W = G m M / Re² (1 - 78.5 10⁻⁶)

Remains

     W = Wo (1 - 7.85  10⁻⁵)

We can see that if the weight theoretically decreases at this height, but in a fraction of 10⁻⁵, which is not appreciable in any scale, therefore, the reading of the scale in the two places is the same.

4 0
3 years ago
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BlackZzzverrR [31]
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A stunt man jumps from the top of a building and lands 10 meters below his initial height. In case A, the stunt man lands on a s
krek1111 [17]

Answer:

Explanation:

The stunt will likely sustain serious injury in case of concrete blocks because the average force acting on the person will be more because concrete blocks do not squeeze to provide more time for the force to act on the body instead it acts for a small amount of interval.

Impulse=F_{avg}\times \Delta T

As impulse is constant so time requires to act force on the body is more as compared to concrete block and thus average force in mattress case is less.  

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Answer:

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almond37 [142]

Answer:

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Explanation:

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  • The potential energy of a body is due to the height from the surface of the earth.

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  • If there is no velocity associated with the body, there is no K.E in the body.
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