<u>Solution and Explanation:</u>
Floating point and Integer consumes 1000 seconds of 1600 seconds.
Since we shall be talking of theoretical speed-up, please do not try to relate this with any practical scenario :P
To achieve maximum speed up, we need to reduce the time consumed by FP and Integer as large as possible. So we consider a system that does not at all consume time to perform FP and Integer operations. With such specifications, we can say that our new system will consume 600 seconds.
speed up = 1600 divide by 600 = 2.66
<u>part b:
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We need a System with enhancement that will result in speedup of 2.
So the time required for the new system would be 800 sec
Required time = 1600 divide by = 800 seconds
It is now given that Floating Point can now be accelerated by 5 times, so our enhanced system will consume 40 seconds to perform Floating point operations
We know that Load/Store and branch operations cannot be enhanced and hence they will consume 600 seconds.
Therefore to attend speedup of 2, Integer operations must be completed in 160 seconds (160 = 800 – (600 + 40))
So speed up required for Integer Operations is 800/160 = 5
So Integer Operation should need 5 times less time to achieve speed up of 2
