Some wire of radius is 1.262mm has a resistance of 20Ω. Determine the resistance of a wire of the same length and material if th
2 answers:
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Answer:
C
Explanation:
Pitot tube:
Pitot tube is a device which is used to measure the velocity of flow by measuring pressure difference between the points.
As we know that stagnation pressure is the summation of dynamic and static pressure.
Stagnation pressure = Static pressure + Dynamic pressure
So
Dynamic pressure = Stagnation pressure - Static pressure
We know that dynamic pressure
On the other hand Pitot tube measure the dynamic pressure.
So option C is correct.
Answer:
A. 288,030.91 cy
B. The amount of water that must be removed from the natural material is 483541.04254 gallons of water
Explanation:
The natural material in the barrow properties are;
The mass unit weight, γ = 110.0 pcf
The water content, w = 6%
The specific gravity of the soil solids, = 2.63
The desired dry unit weight, = 122 pcf
The water content, w₁ = 5.5 %
The net section volume, = 245,000 cy = 6,615,000 ft³
A. =
/
∴ =
×
= 6,615,000 ft³ × 122 lb/ft³ = 807030000 lbs
w = (/
) × 100
∴ = (w/100) ×
= (6/100) × 807030000 lbs = 48421800 lbs
The weight of solids
W = +
= 807030000 lbs + 48421800 lbs = 855451800 lbs
V = W/γ = 855451800 lbs/(110.0 lb/ft.³) = 7776834.54545 ft.³ = 288,030.91 cy
V = 288,030.91 cy
The amount of cubic yards of borrow required = 288,030.91 cy
B. The volume of water in the required soil is found as follows;
= (w₁/100) ×
= (5.5/100) × 807030000 lbs = 44386650 lbs
The amount of water that must be added = -
= 44386650 lbs - 48421800 lbs = -4,035,150 lbs
Therefore, 4,035,150 lbs of water must be removed
The density of water, ρ = 8.345 lbs/gal
Therefore, V = 4,035,150 lbs/(8.345 lbs/gal) = 483541.04254 gal of water must be removed from the natural material