Answer:
<em>The magnitude of the force is 10 N</em>
Explanation:
<u>Coulomb's Law</u>
The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:

Where:

q1, q2 = the objects' charge
d= The distance between the objects
We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:


F = 10 N
The magnitude of the force is 10 N
Answer:
Described below
Explanation:
- The behaviorist theories: This theory is of the claim that language is learned through the means of reinforcement and imitation. This means that little children can mimic the language of individuals around them and also receive reinforcement to correct the formation of their words. Thereafter, words not reinforced will eventually no longer be in use.
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When your in the mountains or in a quiet room
Answer:
The translational kinetic energy is 225 J
The rotational kinetic energy is 225 J
Explanation:
Given;
mass of the wheel, m = 2-kg
linear speed of the wheel, v = 15 m/s
Transnational kinetic energy is calculated as;
E = ¹/₂MV²
where;
M is mass of the moving object
V is the velocity of the object
E = ¹/₂ x 2 x (15)²
E = 225 J
Rotational kinetic energy is calculated as;
E = ¹/₂Iω²
where;
I is moment of inertia
ω is angular velocity

E = ¹/₂ x 2 x (15)²
E = 225 J
Thus, the translational kinetic energy is equal to rotational kinetic energy
Answer:

Explanation:
The final velocity is given by the following kinematic equation:

Here,
is the initial velocity, a is the body's acceleration and t is the motion time. We have to convert the time to seconds:

Now, we calculate the final velocity:
