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3 years ago

11

g The current in a series circuit is 15.0 A. When an additional 8.00-% resistor is inserted in series, the current drops to 12.0

A. What is the resistance in the original circuit

1 answer:

Anna007 [38]3 years ago

5 0

Answer:

Explanation:

Let the original resistance be R and voltage be V

Applying ohm's law

V / R = 15

V = 15 R

In second case

V / (R+8 ) = 12

V = 12 R + 96

15 R = 12 R + 96

3R = 96

R = 32 ohm .

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