Answer:
hope it's help you ok have a good day
Answer:
B
Explanation:
The temperature is proportional to the kinetic energy of the system.
The kinetic energy is a measure of the movement capability of the molecules of the system. Hence, we can directly say molecules moving faster possess more average kinetic energy.
This kinetic energy is a measure of temperature. This is in the sense that the higher the temperature, the higher the degree of turbulnece . This tends to show us that the molecules are moving with greater speed.
Hence, we can conclude that there is a direct degree of proportionality between the temperature and the kinetic energy of the molecules as an increase in temperature causes a corresponding increase in the speed of the molecules
Answer:
The titration process has quite a few real-world uses, including key roles in the food industry and medical community. The titration process is essentially an analytical technique, as it is used to determine a chemical or physical property of a chemical substance, element, or mixture (such as food). Specifically in the food industry, it is used to allow food manufactuers to determine the quantity of a reactant in a sample. To provide an example, it can be used to find the specific amount of stuff that is usually labeled on the nutrition label, such as sugar, salt, protein, calcium, vitamin C, etc. As for the medical world, pharamcists typically use this process to get the proper mix when compounding medicines. It is used to get the necessary proportions in intravenous drips.
Answer:
10.5g
Explanation:
First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:
Volume = 250mL = 250/1000 = 0.25L
Molarity = 0.5M
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.5 x 0.25
Mole = 0.125 mole
Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:
Molar Mass of NaHCO3 = 23 + 1 + 12 +(16x3) = 23 + 1 +12 +48 = 84g/mol
Number of mole of NaHCO3 = 0.125 mole
Mass of NaHCO3 =?
Mass = number of mole x molar Mass
Mass of NaHCO3 = 0.125 x 84
Mass of NaHCO3 = 10.5g
Therefore, 10.5g of NaHCO3 is needed.