El ejercicio completo con las formulas es el siguiente:
cuál de las siguientes fórmulas no cumple con la tetravalencia del átomo de carbono.
a. CH3-CH2-CH2-OH
b. CH3-CH=CH2
c. CH3-CH2=CH2
d. CH3-CH2-CH3
Answer:
La respuesta correcta es la opción C
Explanation:
En la formula C, podemos ver claramente que no se cumple con la tetravalencia del carbono pues al sumar el total de las valencias del carbono nos da 5
CH3 - CH2 = CH2 = Total de valencias del carbono 5
1 + 2+ 2 = 5
Para que la formula sea correcta debe eliminarse un hidrogeno quedando la formula de la siguiente manera:
CH3 - CH = CH2
1 + 1 + 2 = 4
Answer:
12CO2 (g) + 12H2O (l) ⇒ C12H24O12 (s) + 12O2
Explanation:
Start by comparing the moles of carbons on the left to number on the right. The number of moles on both side of the arrow should be the same.
Answer : The correct option is (3) 500 K and 0.1 atm.
Explanation :
A real gas behaves ideally at high temperature and low pressure.
The ideal gas equation is,
where,
P = pressure of gas
V = Volume of gas
R = Gas constant
T = temperature of gas
n = number of moles of gas
The ideal gas works properly when the inter-molecular interactions between the gas molecules and volume of gas molecule will be negligible. This is possible when pressure is low and temperature is high.
Therefore, the correct option is (3) 500 K and 0.1 atm.
Answer: 127 (3.s.f)
Explanation:
Boyle's law states that Volume x pressure = constant
Therefore let's first find the constant: 45 x 1900 = 85500
Then lets plug 675 ml and 85500 into the equation above:
675 x C = 85500
C = 127 (3 s.f.)
The action that would most likely lead to. Decrease in volume is decrease in temperature.
